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我正在編寫一個統計插件,它在加入時從數據庫中檢索統計信息,將它們實現爲散列圖,並在退出時將它們實現到數據庫中,這樣做的原因是,每秒鐘都沒有像開放式連接那麼多滯後。從我的代碼中獲取我的控制檯中的一些錯誤
如果這意味着什麼,我正在使用MariaDB。
包含HashMap下面
public static HashMap<String, Integer> kills = new HashMap<String, Integer>();
public static HashMap<String, Integer> deaths = new HashMap<String, Integer>();
下面的代碼
@EventHandler
public void onDeath(PlayerDeathEvent event){
Player p = event.getEntity();
Player k = p.getKiller();
kills.put(k.getName(), kills.get(k.getName() + 1));
deaths.put(p.getName(), deaths.get(p.getName() + 1));
removeScoreboard(p);
setScoreboard(p);
removeScoreboard(k);
setScoreboard(k);
}
@EventHandler
public void onJoin(PlayerJoinEvent e){
OfflinePlayer p2 = e.getPlayer();
Player p = e.getPlayer();
openConnection();
try{
int previousDeaths = 0;
int previousKills = 0;
if(playerDataContainsPlayer(p)){
PreparedStatement sql = connection.prepareStatement("SELECT deaths FROM `player_data` WHERE player=?;");
PreparedStatement sql2 = connection.prepareStatement("SELECT kills FROM `player_data` WHERE player=?;");
ResultSet result = sql.executeQuery();
ResultSet result2 = sql2.executeQuery();
result2.next();
result.next();
previousDeaths = result.getInt("deaths");
previousKills = result2.getInt("kills");
kills.put(p.getName(), previousKills);
deaths.put(p.getName(), previousDeaths);
sql.close();
sql2.close();
result.close();
result2.close();
removeScoreboard(p);
setScoreboard(p);
} else {
PreparedStatement newPlayer = connection.prepareStatement("INSERT INTO `player_data` values(?,0,0);");
newPlayer.setString(1, p.getUniqueId().toString());
newPlayer.setInt(2, 0);
newPlayer.setInt(3, 0);
newPlayer.execute();
newPlayer.close();
kills.put(p.getName(), 0);
deaths.put(p.getName(), 0);
removeScoreboard(p);
setScoreboard(p);
}
}catch(Exception e1){
e1.printStackTrace();
} finally{
closeConnection();
}
}
@EventHandler
public void onLeave(PlayerQuitEvent e){
Player p = e.getPlayer();
openConnection();
try{
int previousDeaths = 0;
int previousKills = 0;
if(playerDataContainsPlayer(p)){
PreparedStatement sql = connection.prepareStatement("SELECT deaths FROM `player_data` WHERE player=?;");
PreparedStatement sql2 = connection.prepareStatement("SELECT kills FROM `player_data` WHERE player=?;");
sql.setString(1, p.getUniqueId().toString());
sql2.setString(1, p.getUniqueId().toString());
ResultSet result = sql.executeQuery();
ResultSet result2 = sql2.executeQuery();
result2.next();
result.next();
previousDeaths = result.getInt("deaths");
previousKills = result2.getInt("kills");
PreparedStatement killsUpdate = connection.prepareStatement("UPDATE `player_data` SET kills=? WHERE player=?;");
killsUpdate.setInt(1, kills.get(p.getName()));
killsUpdate.setString(2, p.getUniqueId().toString());
killsUpdate.executeUpdate();
PreparedStatement deathsUpdate = connection.prepareStatement("UPDATE `player_data` SET deaths=? WHERE player=?;");
deathsUpdate.setInt(1, deaths.get(p.getName()));
deathsUpdate.setString(2, p.getUniqueId().toString());
deathsUpdate.executeUpdate();
deathsUpdate.close();
killsUpdate.close();
sql.close();
sql2.close();
result.close();
result2.close();
}
}catch(Exception e1){
e1.printStackTrace();
} finally{
closeConnection();
}
}
只要你加入,它說[20時51分43秒WARN]:java.sql.SQLException中:沒有爲參數1
指定值而且每當你殺死某人或死亡時,你的殺戮都是空的,你的死亡則是空的。我不知道爲什麼發生這種情況,任何幫助表示讚賞。
?你知道爲什麼HashMaps這樣不工作? – Awaken
此外,我不想在Join上設置Integers,我想檢索整數,並將它們保存在Leave中。 – Awaken
hashmap有什麼問題? –