當所有列表中存在(至少1個)和最喜歡的樂隊(可能> 3)時,我必須創建一個列表清單的代碼,其中它返回「True」。我對編程非常陌生,而且我很遺憾要做什麼。我嘗試了一些東西,但沒有完全填充,我需要一些幫助!Python-列表列表
favoriteBandLists = [
["Metallica","Linkin Park","Alice In Chains","Nirvana", "Soundgarden"],
["Pink Floyd","Alice In Chains","Soundgarden","Metallica","Linkin Park"],
["Audioslave","Offspring","Soundgarden","Linkin Park","The Beatles"]]
我的代碼:
def commonFavoriteBand(list):
foundCounterExampleyet = False
for i in range(()):
if(()):
foundCounterExampleYet = True
return not(foundCounterExampleYet)
print (commonFavoriteBand())
def commonFavoriteBandA():
foundExampleYet = False
for value in values:
if():
foundExampleYet = True
return foundExampleYet
你能仔細檢查你的發佈代碼的縮進嗎?很難看到那裏發生了什麼.. – msturdy 2014-12-11 03:11:47
@msturdy是否有縮進的具體方法?我很抱歉我在這裏有一種新的 – 2014-12-11 03:18:16
複製你的代碼到框中,選擇它,然後按Ctrl + k – msturdy 2014-12-11 03:21:40