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我想創建一個Sudoku拼圖，所以我想出了這個python代碼，下面是打印一個字典，其鍵是從Btns列表，但是當運行代碼沒有完成該任務也不會給出任何錯誤消息。我需要幫助解密問題可能是什麼以及如何解決問題。循環沒有完成它的任務
from random import randint
Btns = ['A11', 'A12', 'A13', 'A21', 'A22', 'A23', 'A31', 'A32', 'A33',
'B14', 'B15', 'B16', 'B24', 'B25', 'B26', 'B34', 'B35', 'B36',
'C17', 'C18', 'C19', 'C27', 'C28', 'C29', 'C37', 'C38', 'C39',
'D41', 'D42', 'D43', 'D51', 'D52', 'D53', 'D61', 'D62', 'D63',
'E44', 'E45', 'E46', 'E54', 'E55', 'E56', 'E64', 'E65', 'E66',
'F47', 'F48', 'F49', 'F57', 'F58', 'F59', 'F67', 'F68', 'F69',
'G71', 'G72', 'G73', 'G81', 'G82', 'G83', 'G91', 'G92', 'G93',
'H74', 'H75', 'H76', 'H84', 'H85', 'H86', 'H94', 'H95', 'H96',
'I77', 'I78', 'I79', 'I87', 'I88', 'I89', 'I97', 'I98', 'I99']
H1 = list(range(1,10))
H2 = list(range(1,10))
H3 = list(range(1,10))
H4 = list(range(1,10))
H5 = list(range(1,10))
H6 = list(range(1,10))
H7 = list(range(1,10))
H8 = list(range(1,10))
H9 = list(range(1,10))
V1 = list(range(1,10))
V2 = list(range(1,10))
V3 = list(range(1,10))
V4 = list(range(1,10))
V5 = list(range(1,10))
V6 = list(range(1,10))
V7 = list(range(1,10))
V8 = list(range(1,10))
V9 = list(range(1,10))
A = list(range(1,10))
B = list(range(1,10))
C = list(range(1,10))
D = list(range(1,10))
E = list(range(1,10))
F = list(range(1,10))
G = list(range(1,10))
H = list(range(1,10))
I = list(range(1,10))
the_game = {}
#iterating through Btns
for btns in Btns:
first = btns[0]
second = btns[1]
third = btns[2]
r = randint(1, 9)
#Assigning an array to first_list
if first == 'A':
first_list = A
elif first == 'B':
first_list = B
elif first == 'C':
first_list = C
elif first == 'D':
first_list = D
elif first == 'E':
first_list = E
elif first == 'F':
first_list = F
elif first == 'G':
first_list = G
elif first == 'H':
first_list = H
else:
first_list = I
#Assigning an array to second_list
if second == '1':
second_list = H1
elif second == '2':
second_list = H2
elif second == '3':
second_list = H3
elif second == '4':
second_list = H4
elif second == '5':
second_list = H5
elif second == '6':
second_list = H6
elif second == '7':
second_list = H7
elif second == '8':
second_list = H8
else:
second_list = H9
#Assigning an array to third_list
if third == '1':
third_list = V1
elif third == '2':
third_list = V2
elif third == '3':
third_list = V3
elif third == '4':
third_list = V4
elif third == '5':
third_list = V5
elif third == '6':
third_list = V6
elif third == '7':
third_list = V7
elif third == '8':
third_list = V8
else:
third_list = V9
#Making sure r is contained in the three lists
while (r not in first_list) or (r not in second_list) or (r not in third_list):
r = randint(1, 9)
print(r)
print(first_list)
print(second_list)
print(third_list)
the_game[btns] = r # Adding r to the dictionary
#Removing r from the three lists
first_list.remove(r)
second_list.remove(r)
third_list.remove(r)
print(the_game)
想一想，如果你需要這麼多的實例變量重複。你可以用一個數組來完成這個任務。 – Ares
@Ekene，歡迎來到Stack Overflow！你的代碼中有一個「無限循環」。工作是找出它是在外部的「for」還是在內部的「while」循環中。我建議你縮小你的嘗試。首先，做一個9元素Btns陣列;然後爲原來的81個元素做。這是迪克斯特拉在工作中的分而治之的方法。希望能幫助到你。好的編碼！ – ranieribt