如果條件在python中不起作用

Question

import light 
import urllib2 

true = 1 
while(true): 
       try: 
         response = urllib2.urlopen('http://192.168.1.6/light.php') 
         status = response.read() 
       except urllib2.HTTPError, e: 
             print e.code 

       except urllib2.URLError, e: 
             print e.args 

       print status 
       if status=='17': 
         light.lighton(); 
       elif status=='0': 
         light.lightoff(); 

Answer 1

狂猜：你的響應以換行符結束。試試這個：

  status = status.strip() 
      print status 
      if status=='17': 
        light.lighton(); 
      elif status=='0': 
        light.lightoff();