我正在一個擁有用戶配置文件的網站上工作,我設法完成了註冊頁面,一旦用戶激活了這個帳戶,他們將有權登錄。多個PHP錯誤
基本上我寫出我的登錄腳本,當我查看網站時,我有兩個錯誤,他們真的很混亂[錯誤1]:注意:未定義的索引:loginEmail在C:\ xampp \ htdocs \ mountain-bikers \ index.php on line 160 [錯誤2]:注意:未定義的索引:記得在C:\ xampp \ htdocs \ mountain-bikers \ index.php上線166 return_msg = no_good
這裏是登錄php代碼:
<?php
if ($_POST['loginEmail'] != "") {
include_once "includes/mysql_connection.php";
$loginEmail = $_POST['loginEmail'];
$loginPassword = $_POST['loginPassword'];
$loginRemember = $_POST['remember'];
$loginEmail = strip_tags($loginEmail);
$loginPassword = strip_tags($loginPassword);
$loginEmail = mysql_real_escape_string($loginEmail);
$loginPassword = mysql_real_escape_string($loginPassword);
$pass = md5($loginPassword);
//make query
$sql = mysql_query("SELECT * FROM users WHERE email='$loginEmail' AND password='$loginPassword' AND activated='1'");
$login_check = mysql_num_rows($sql);
if($login_check > 0){
while($row = mysql_fetch_array($sql)){
$id = $row["id"];
session_register('id');
$_SESSION['id'] = $id;
$firstname = $row["firstname"];
session_register('firstname');
$_SESSION['firstname'] = $firstname;
$email = $row["email"];
session_register('email');
$_SESSION['loginEmail'] = $email;
} // close while
// Remember Me Section Addition... if member has chosen to be remembered in the system
if($remember == "yes"){
setcookie("idCookie", $id, time()+60*24*60*60, "/"); // 60 days; 24 hours; 60 mins; 60secs
setcookie("firstnameCookie", $firstname, time()+60*24*60*60, "/"); // 60 days; 24 hours; 60 mins; 60secs
setcookie("emailCookie", $email, time()+60*24*60*60, "/"); // 60 days; 24 hours; 60 mins; 60secs
setcookie("passwordCookie", $password, time()+60*24*60*60, "/"); // 60 days; 24 hours; 60 mins; 60secs
}
$my_msg = "all_good";
print "return_msg=$my_msg&id=$id&firstname=$firstname";
} else {
$my_msg = "no_good";
print "return_msg=$my_msg";
exit();
}
}// close if post
?>
我也收到了電子郵件和密碼字段的未定義變量錯誤。此外,登錄在每個字段中都有一個value="<?php print "$loginEmail"; ?>"
。如果你需要HTML只是問。
見'isset()函數'http://www.php.net/manual/en/function.isset.php –
你只需要更小心你的變量聲明。像這樣的錯誤是很常見的;如果你確保初始化變量並使用'isset()',你將能夠阻止它們。 –