如何使Windows服務保持運行

Question

以下是我正在運行的Windows服務的框架。如果發生錯誤，則會記錄錯誤並可以在事件查看器中查看。問題是腳本退出並且不會重新啓動，即使我已將恢復設置爲在第一次，第二次和隨後的故障時重新啓動服務。目前我的錯誤處理很少，因爲我想查看事件查看器中可能出現的錯誤，以便我可以編寫相應的代碼來處理這些錯誤。

from win32api import CloseHandle, GetLastError, SetConsoleCtrlHandler 
import os 
import sys 
import time 
import pythoncom 
import win32serviceutil 
import win32service 
import win32event 
import servicemanager 
import socket 

class AppServerSvc (win32serviceutil.ServiceFramework): 
    _svc_name_ = "my_service_name" 
    _svc_display_name_ = "my service" 

    def __init__(self,args): 
     win32serviceutil.ServiceFramework.__init__(self,args) 
     SetConsoleCtrlHandler(lambda x: True, True) 
     self.hWaitStop = win32event.CreateEvent(None,0,0,None) 

    def SvcStop(self): 
     self.ReportServiceStatus(win32service.SERVICE_STOP_PENDING) 
     win32event.SetEvent(self.hWaitStop) 
     self.run = False 

    def SvcDoRun(self): 
     servicemanager.LogMsg(servicemanager.EVENTLOG_INFORMATION_TYPE, 
           servicemanager.PYS_SERVICE_STARTED, 
           (self._svc_name_,'')) 
     self.run = True 
     self.main() 

    def main(self): 
     while self.run == True 
      pass   

if __name__ == '__main__': 
    win32serviceutil.HandleCommandLine(AppServerSvc) 

編輯：

我想嘗試：除了圍繞self.main但是結果還是一樣。該服務在崩潰時不會重新啓動...請任何人有任何想法？如果它不能在發生碰撞的情況下，重新啓動服務是不是所有的有用......還不如運行它作爲一個.pyc文件

編輯：

下面

是中可能出現的錯誤的例子我的腳本......我不相信這個錯誤消息是特別有用的，因爲我試圖實現的是讓服務重新啓動，但是這裏沒有一個是在沒有重新啓動的情況下崩潰我的服務的錯誤的示例：

The instance's SvcRun() method failed 
Traceback (most recent call last): 
    File "C:\Python27\lib\site-packages\win32\lib\win32serviceutil.py", line 806, in SvcRun 
    self.SvcDoRun() 
    File "C:\Some_Service.py", line 46, in SvcDoRun 
    self.main() 
    File "Some_Service.py", line 61, in main 
    ser = self.open_serial_port() 
    File "Some_Service.py", line 70, in open_serial_port 
    serial_connection.open() 
    File "C:\Python27\lib\site-packages\serial\serialwin32.py", line 56, in open 
    raise SerialException("could not open port %s: %s" % (self.portstr, ctypes.WinError())) 
SerialException: could not open port COM6: [Error 1225] The remote system refused the network connection. 
%2: %3 

Answer 1

下面是一個以零分出錯的服務。如果發生錯誤，則會發送事件並使用os._exit(-1)退出服務。該值必須是0以外的任何值，以便窗口知道服務沒有很好地退出。

from win32api import CloseHandle, GetLastError, SetConsoleCtrlHandler 
import os 
import sys 
import time 

import win32serviceutil 
import win32service 
import win32event 
import servicemanager 

import traceback 



class AppServerSvc (win32serviceutil.ServiceFramework): 
    _svc_name_ = "test" 
    _svc_display_name_ = "test" 

    def __init__(self,args): 
     win32serviceutil.ServiceFramework.__init__(self,args) 
     SetConsoleCtrlHandler(lambda x: True, True) 
     self.hWaitStop = win32event.CreateEvent(None,0,0,None) 




    def SvcStop(self): 
     self.ReportServiceStatus(win32service.SERVICE_STOP_PENDING) 
     win32event.SetEvent(self.hWaitStop) 
     self.run = False 
    def SvcDoRun(self): 

     servicemanager.LogMsg(servicemanager.EVENTLOG_INFORMATION_TYPE, 
           servicemanager.PYS_SERVICE_STARTED, 
           (self._svc_name_,'')) 
     self.run = True 
     try: # try main 
      self.main() 
     except: 
      servicemanager.LogErrorMsg(traceback.format_exc()) # if error print it to event log 
      os._exit(-1)#return some value other than 0 to os so that service knows to restart 


    def main(self): 

     while self.run == True: 
      time.sleep(30)   
      t = 1/0 

if __name__ == '__main__': 
    win32serviceutil.HandleCommandLine(AppServerSvc) 

Answer 2

我懷疑你的服務實際上並沒有崩潰，而是在它有機會運行之前完成。您是否嘗試在main函數中插入幾秒鐘的睡眠聲明？

Answer 3

爲什麼不使用try-except？

class AppServerSvc (win32serviceutil.ServiceFramework): 
    _svc_name_ = "my_service_name" 
    _svc_display_name_ = "my service" 

    def __init__(self,args): 
     win32serviceutil.ServiceFramework.__init__(self,args) 
     SetConsoleCtrlHandler(lambda x: True, True) 
     self.hWaitStop = win32event.CreateEvent(None,0,0,None) 

    def SvcStop(self): 
     self.ReportServiceStatus(win32service.SERVICE_STOP_PENDING) 
     win32event.SetEvent(self.hWaitStop) 
     self.run = False 

    def SvcDoRun(self): 
     servicemanager.LogMsg(servicemanager.EVENTLOG_INFORMATION_TYPE, 
           servicemanager.PYS_SERVICE_STARTED, 
           (self._svc_name_,'')) 
     self.run = True 
     self.main() 

    def main(self): 
     while self.run == True 
      try : 
       <your code> 
      except : 
       time.sleep(3) 
       <may be an error log here> 



if __name__ == '__main__': 
    win32serviceutil.HandleCommandLine(AppServerSvc)