反序列化錯誤：「<book xmlns ='>不是預期的。」從xml字符串DeSerialize

Question

我有問題將xml反序列化到多個類對象。當我嘗試喲反序列化 我越來越「沒有預料到」。

這裏是我的調用代碼

StringReader strReader = new StringReader(xml);   
XmlTextReader reader = new XmlTextReader(strReader); 
reader.ReadToDescendant("book"); 
var temp = DeserializeFromXml<book>(reader.ReadOuterXml()); 

public static T DeserializeFromXml<T>(string xml) 
    { 
     T result; 
     XmlRootAttribute xRoot = new XmlRootAttribute(); 
     XmlSerializer ser = new XmlSerializer(typeof(T)); 
     using (TextReader tr = new StringReader(xml)) 
     { 
      result = (T)ser.Deserialize(tr); 
     } 
     return result; 
    } 

XML是字符串消息

<?xml version="1.0" encoding="UTF-8"?><books xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" > 
<book genre="novel"> 
    <title>The Handmaid's Tale</title> 
    <price>19.95</price> 
    <ISBN>1-861003-78</ISBN> 
    <style>hardcover</style> 
</book> 
<library genre="novel"> 
    <name>Oxford</name> 
    <location>london</location> 
    <ISBN>1-8888888-88</ISBN> 
    <address>12th main, chesmedia</address> 
</library> 

當我嘗試執行此代碼我得到這個內部異常 「是沒有預料到。」

這裏是我的類代碼

[System.CodeDom.Compiler.GeneratedCodeAttribute("System.Xml", "4.0.30319.233")] 
[System.SerializableAttribute()] 
[System.ComponentModel.DesignerCategoryAttribute("code")] 
[System.Xml.Serialization.XmlTypeAttribute(AnonymousType = true, Namespace = "http://tempuri.org/SampleBooks.xsd")] 
[System.Xml.Serialization.XmlRootAttribute(Namespace = "http://tempuri.org/SampleBooks.xsd", IsNullable = false)] 
public partial class books 
{ 

    private book bookField; 

    private library libraryField; 

    private static System.Xml.Serialization.XmlSerializer serializer; 

    public books() 
    { 
     this.libraryField = new library(); 
     this.bookField = new book(); 
    } 

    [System.Xml.Serialization.XmlElementAttribute(Order = 0)] 
    public book book 
    { 
     get 
     { 
      return this.bookField; 
     } 
     set 
     { 
      this.bookField = value; 
     } 
    } 

    [System.Xml.Serialization.XmlElementAttribute(Order = 1)] 
    public library library 
    { 
     get 
     { 
      return this.libraryField; 
     } 
     set 
     { 
      this.libraryField = value; 
     } 
    } 

    private static System.Xml.Serialization.XmlSerializer Serializer 
    { 
     get 
     { 
      if ((serializer == null)) 
      { 
       serializer = new System.Xml.Serialization.XmlSerializer(typeof(books)); 
      } 
      return serializer; 
     } 
    } 

} 

[System.CodeDom.Compiler.GeneratedCodeAttribute("System.Xml", "4.0.30319.233")] 
[System.SerializableAttribute()] 
[System.ComponentModel.DesignerCategoryAttribute("code")] 
[System.Xml.Serialization.XmlTypeAttribute(AnonymousType = true, Namespace = "http://tempuri.org/SampleBooks.xsd")] 
[System.Xml.Serialization.XmlRootAttribute(Namespace = "http://tempuri.org/SampleBooks.xsd", IsNullable = false)] 
public partial class book 
{ 

    private title titleField; 

    private decimal priceField; 

    private ISBN iSBNField; 

    private style styleField; 

    private bookGenre genreField; 

    private static System.Xml.Serialization.XmlSerializer serializer; 

    [System.Xml.Serialization.XmlElementAttribute(Order = 0)] 
    public title title 
    { 
     get 
     { 
      return this.titleField; 
     } 
     set 
     { 
      this.titleField = value; 
     } 
    } 

    [System.Xml.Serialization.XmlElementAttribute(Order = 1)] 
    public decimal price 
    { 
     get 
     { 
      return this.priceField; 
     } 
     set 
     { 
      this.priceField = value; 
     } 
    } 

    [System.Xml.Serialization.XmlElementAttribute(Order = 2)] 
    public ISBN ISBN 
    { 
     get 
     { 
      return this.iSBNField; 
     } 
     set 
     { 
      this.iSBNField = value; 
     } 
    } 

    [System.Xml.Serialization.XmlElementAttribute(Order = 3)] 
    public style style 
    { 
     get 
     { 
      return this.styleField; 
     } 
     set 
     { 
      this.styleField = value; 
     } 
    } 

    [System.Xml.Serialization.XmlAttributeAttribute()] 
    public bookGenre genre 
    { 
     get 
     { 
      return this.genreField; 
     } 
     set 
     { 
      this.genreField = value; 
     } 
    } 

    private static System.Xml.Serialization.XmlSerializer Serializer 
    { 
     get 
     { 
      if ((serializer == null)) 
      { 
       serializer = new System.Xml.Serialization.XmlSerializer(typeof(book)); 
      } 
      return serializer; 
     } 
    } 

} 

Answer 1

簡單地脫掉命名空間=從圖書類的屬性。 所以你的代碼將會像

[System.CodeDom.Compiler.GeneratedCodeAttribute("System.Xml", "4.0.30319.233")] 
    [System.SerializableAttribute()] 
    [System.ComponentModel.DesignerCategoryAttribute("code")] 
    [System.Xml.Serialization.XmlTypeAttribute(AnonymousType = true, Namespace = "http://tempuri.org/SampleBooks.xsd")] 
    [System.Xml.Serialization.XmlRootAttribute(IsNullable = false)] 
    public partial class book