以一種形式插入和更新

Question

昨天我的問題是關於插入和更新的一種形式，我做了，但數據插入，當我點擊編輯鏈接，它可以在displayp.php它顯示所有數據的字段，但是當我更新任何數據，並點擊提交按鈕其不更新，但它下一次插入數據在數據庫中，我在數據庫中獲取多個記錄。其實我已經把插入和更新中，如果當我更新它不是在其他部分動，所以請幫我...條件謝謝..

<div id="page-wrapper" > 
<div id="page-inner"> 
<div class="row"> 
    <div class="col-md-12"> 
     <h2>Add Product</h2> 
    </div> 
</div> 
<!-- /. ROW --> 
<hr /> 
<div class="row"> 
<?php 
    include('config.php'); 
    if($_SERVER['REQUEST_METHOD']=='POST') 
    { 
    if(isset($_POST['submit'])=='POST') 
    { 

    echo "working"; 
    $fileName=$_FILES["filepdf"]["name"]; 
    $fileSize=$_FILES["filepdf"]["size"]/2024; 
    $fileType=$_FILES["filepdf"]["type"]; 
    $fileTmpName=$_FILES["filepdf"]["tmp_name"]; 

    if($fileType=="application/pdf"){ 
    if($fileSize<=200){ 

    //New file name 
    $random=rand(1111,9999); 
    $newFileName=$random.$fileName; 

    //File upload path 
    $uploadPath="testUpload/".$newFileName; 

    //function for upload file 

    if(move_uploaded_file($fileTmpName,$uploadPath)) 
    { 
    echo "Successful<BR>"; 
    echo "File Name :".$newFileName."<BR>"; 
    echo "File Size :".$fileSize." kb"."<BR>"; 
    echo "File Type :".$fileType."<BR>"; 
    } 
    else 
    { 


    echo "Maximum upload file size limit is 200 kb"; 
    } 
    } 
    else 
    { 


    return false; 


    echo "You can only upload a pdf doc file."; 
    } 


     echo "here downld"; 


    $updates = isset($_POST['updates']) ? 'Yes' : 'No'; 

     $catnm=$_POST['catnm']; 
     $prodnm=$_POST['prodnm']; 
     $prod_dtl=$_POST['prod_dtl']; 

     //$updates=$_POST['downld']; 
     $date=$_POST['date']; 



    $query=("insert into addproduct(catnm,prodnm,prod_dtl,pdf,downld,date) 


    values('$catnm','$prodnm','$prod_dtl','$uploadPath','$updates','$date')"); 
     $result = mysql_query($query,$conn); 
     echo"record inserted"; 
     if($result) 
     { 
      header("location:addProduct.php"); 
     } 
    } 

    } 
    } 
    else if($_SERVER['REQUEST_METHOD']=='GET') 
    { 
    if(isset($_GET['id'])) 
    { 

    $id = $_GET['id']; 
    if(isset($_POST['submit'])) 
    { 




    $updates['downld'] = isset($_POST['downld']) ? 'Yes' : 'No'; 
    $cat['catnm']=$_POST['catnm']; 
    $prodnm['prodnm']=$_POST['prodnm']; 
    $prod_dtl['prod_dtl']=$_GET['prod_dtl']; 
    $pdf['pdf']=$_GET['pdf']; 
    $downld['downld']=$_GET['downld']; 
    $date['date']=$_GET['date']; 



    $query3=mysql_query("update addproduct set catnm='$cat',    
    prodnm='$prodnm',prod_dtl='$prod_dtl' 


    ,pdf='$pdf',downld='$updates',date='$date' where id='$id'"); 

    if($query3) 
    { 
     header('location:addProduct.php'); 
    } 
    } 


    $query1=mysql_query("select * from addproduct where id='$id'"); 
    $query4=mysql_fetch_array($query1); 
    //echo "<pre>"; 
    //print_r($query4); 
    } 
    } 
    ?> 
<div class="col-md-6 col-sm-12 col-xs-12"> 
    <div class="panel-body"> 
     <form role="form" method="post" 
     enctype="multipart/form-data" name="myform" > 
     <br/> 
     <label>Select Category:</label>  
     <div class="form-group"> 
      <?php 
       include('config.php'); 


       $query1=mysql_query("select catnm from addcategory"); 
       ?> 
      <select class=form-control m-b-10 name=catnm id=catnm > 
      <?php 
       echo"<option>---Select---</option required>"; 
       while($query=mysql_fetch_array($query1)) 
       { 

        $selectedCat = ''; 
        if($query[catnm] == $query4['catnm']) 
        { 
         $selectedCat = "selected"; 
        } 



       echo "<option value='$query[catnm]' $selectedCat >$query[catnm]</option>"; 


       } 

       ?>          
      </select> 
      <br/>     
      <div class="form-group"> 
       <input type="text" class="form-control" 
        id="prodnm" placeholder="Product Name" name="prodnm" required 
        value= " <?php if(isset($query4['prodnm'])){echo $query4['prodnm'];}?>"/> 
      </div> 
      <div class="form-group">   
       <textarea class="form-control" id="catdtl" 
        name="prod_dtl" placeholder="Product Detail" 
        "rows="10" cols="62" required> 
       <?php if(isset($query4['prod_dtl'])){ 
        echo $query4['prod_dtl'];} ?> 
       </textarea> 
      </div> 
      <div class="form-group"> 
       <label for="exampleInputFile">PDF File</label> 
       <input type="file" id="exampleInputFile" 
        accept="application/pdf" name="filepdf" required > 
       file : <?php if(isset($query4['pdf'])){ 
        echo $query4['pdf'];} ?>       
      </div> 
      <div class="checkbox"> 
       <label> 
       <input id="checkbox" type="checkbox" name="updates" required 
        <?php if(isset($query4['downld'])) 
        { if($query4['downld'] == 'Yes') 
        echo "checked='checked'"; echo $query4['downld'];} 
           ?> /> 
       Is Downloadable <br /> 
       </label> 
      </div> 
      <input type="text" 
       placeholder="Date of Upload" id="datepicker-7" 
       name="date" value="<?php if(isset($query4['date'])){ 
        echo $query4['date'];}?>" required /> 
      <div style="padding-top:20px;padding-bottom:40px;width:650px;"> 
       <input type="submit" name="submit" id="button" tabindex="2"/> 
       <hr/> 
     </form> 
     </div> 
     <!-- /. ROW --> 
     </div> 
     <!-- /. PAGE INNER --> 
    </div> 
    <!-- /. PAGE WRAPPER --> 
</div> 
</body> 
</html> 

Answer 1

昨天我回答你，但你不添加一個隱藏的輸入帶ID。你可以這樣做嗎？

insert and update in one form in php

而且，你怎麼想象這後在GET？

if(isset($_GET['id'])) 
{ 

$id = $_GET['id']; 
if(isset($_POST['submit'])) 
{ 

* * * 
} 
}