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嘗試生成基於父 - >子結構的db驅動菜單。所有根菜單項父列的值是0。Geeting以下錯誤不斷PHP函數問題
Undefined offset: 0,1,2 on line list($id, $parent, $name) = $results;
Undefined index on line array_key_exists() expects exactly 2 parameters, 1 given on line if (!array_key_exists($tree[$parent]['children'][$id])) {
Warning: array_key_exists() expects exactly 2 parameters, 1 given on line if (!array_key_exists($tree[$parent]['children'][$id])) {
PHP代碼
<?php
function generateMenu($parent, $level, $menu, $utype) {
global $db;
$tree = array();
$stmt = $db->prepare("select id, parent, name FROM navigation WHERE menu=? AND user_type=?") or die($db->error);
$stmt->bind_param("ii", $menu, $utype) or die($stmt->error);
$stmt->execute() or die($stmt->error);
$stmt->store_result();
$meta = $stmt->result_metadata();
$bindResult = array();
while ($columnName = $meta->fetch_field()) {
$bindResult[] = &$results[$columnName->name];
}
call_user_func_array(array($stmt, 'bind_result'), $bindResult);
while ($stmt->fetch()) {
list($id, $parent, $name) = $results;
$tree[$id] = array('name' => $name, 'children' => array(), 'parent' => $parent);
if (!array_key_exists($id, $tree[$parent]['children'])) {
$tree[$parent]['children'][$id] = $id;
}
}
$stmt->close();
print_r($tree);
}
?>
和DB結構
對於測試目的
- 試過
die(print_r($results));
while ($stmt->fetch()) {
之後。獲取我的數據庫表的第一行爲Array ( [id] => 1 [parent] => 0 [name] => Sual) 1
。 試過
上線array_key_existswhile ($results=$stmt->fetch()) {
而不是while ($stmt->fetch()) {
。得到了下面的錯誤再次未定義指數()預計2個參數,1線給出的,如果(!array_key_exists($樹[$父] [ '孩子'] [$ ID])){
警告:array_key_exists()預計2個參數,1線給出的,如果(array_key_exists($樹[$父] [ '孩子'] [$ ID])!){
嘗試
if (!array_key_exists($id, $tree[$parent]['children'])) {
代替if (!array_key_exists($tree[$parent]['children'][$id])) {
。再次出現以下錯誤未定義的偏移量:0,1,2在行列表($ id,$ parent,$ name)= $ results;
不知道,怎麼了。請幫助解決該問題
如果可能,請修改代碼。它會是什麼樣子? –
在list($ id,$ parent,$ name)= $ results之後嘗試了'print_r($ results);'它回顯了所有行'Array([id] => 4 [parent] => 1 [姓名] => Yeni sual)'是的你是對的。但是我必須解決什麼?請修改代碼 –
你在那裏交配? –