這是我DateBaseHelper 公共光標getQuestionsFromQuizID(INT quizID){Android如何獲得隨機sqlite數據?
Integer quiz = Integer.valueOf(quizID);
return myDataBase.rawQuery("select * from Questions where quizID ="+quiz.toString(), null);
}
public Cursor getAnswersFromQuestionID(int questionID, int quizID){
Integer question = Integer.valueOf(questionID);
Integer quiz = Integer.valueOf(quizID);
return myDataBase.rawQuery("select * from Answers where questionID = "+question.toString()+" and quizID = "+quiz.toString(), null);
}
public Boolean isAnswerCorrect(int answerID) {
Integer answer = Integer.valueOf(answerID);
int correctBit;
Cursor cursor = myDataBase.rawQuery("select * from Answers where _id ="
+ answer.toString(), null);
cursor.moveToFirst();
correctBit = cursor.getInt(3);
if (correctBit == 1) {
return true;
} else {
return false;
}
}
public int getQuestionCountByQuizID(int quizID){
Integer quiz = Integer.valueOf(quizID);
Cursor cursor = myDataBase.rawQuery("select * from Questions where quizID ="+quiz.toString(), null);
cursor.moveToFirst();
return cursor.getCount();
}
......我有方法)競猜活動
私人無效getNextQuestion({ 字符串的問題;
// set question count text at the top of screen using string
// concatenation
Integer currentCount = new Integer(curQuestion + 1);
((TextView) findViewById(R.id.questioncount)).setText("Question "
+ currentCount.toString() + " of "
+ totalQuestionCount.toString());
// get quizID based on which button was pressed on PickQuizActivity
int quizID = getIntent().getExtras().getInt("quizID");
// use returned cursor to get question as string
Cursor questionCursor = myDbHelper.getQuestionsFromQuizID(quizID);
questionCursor.moveToPosition(curQuestion);
// getString(3): gets the zero-indexed column 2 from current row cursor
// is on
question = questionCursor.getString(2);
// update UI to show question pulled from database
((TextView) findViewById(R.id.question)).setText(question);
Cursor answerCursor = myDbHelper.getAnswersFromQuestionID(
curQuestion + 1, quizID);
// set each answer text, there will always be 4 answers
// also collect questionID for isCorrect check when onClick is called
answerCursor.moveToFirst();
((TextView) findViewById(R.id.answer1)).setText(answerCursor
.getString(4));
answerID1 = answerCursor.getInt(0);
answerCursor.moveToNext();
((TextView) findViewById(R.id.answer2)).setText(answerCursor
.getString(4));
answerID2 = answerCursor.getInt(0);
answerCursor.moveToNext();
((TextView) findViewById(R.id.answer3)).setText(answerCursor
.getString(4));
answerID3 = answerCursor.getInt(0);
answerCursor.moveToNext();
((TextView) findViewById(R.id.answer4)).setText(answerCursor
.getString(4));
answerID4 = answerCursor.getInt(0);
// increment question counter, will be used to retrieve next question
curQuestion++;
// set flag for last question reached
if (questionCursor.isLast()) {
lastQuestionReached = true;
}
}
所以......當我不會表現出隨機的問題,我編輯SQL,只需添加排序隨機的()LIMIT 10 和我的問題得到的答案混合起來......
任何人可以知道解決方案如何獲得隨機問題而不重複? 如何避免混合問題和答案中的數據?
打開你的答案。你能告訴我如何通過混合問題和答案的數據來解決問題嗎? –
上面編輯的答案。隨意就此提出更多問題,今天我只是在家裏放鬆一下。 – HalR