2
我在表單上有2個選擇菜單:類型和類別。當用戶從類型菜單中選擇一些內容時,我希望它執行一個查詢數據庫的PHP腳本,並返回所選類型的匹配類別列表供他們從類別菜單中選擇。AJAX將表添加到表單元格
這是行之有效的,但我現在想更新它,以便它添加類categoryGroup(「成功」或「錯誤」取決於AJAX結果)。這裏是我的表在2個單元:
<div class="form-group">
<label for="title" class="control-label col-sm-3">Type</label>
<div class="input-group col-xs-8">
<select class="form-control" name="type" id="type" onchange="getCategories(this.value)">
<option value="" selected></option>
<option value="Business">Business</option>
<option value="Commercial">Commercial</option>
<option value="Commercial Land">Commercial Land</option>
<option value="Land">Land</option>
<option value="Rental">Rental</option>
<option value="Residential">Residential</option>
<option value="Rural">Rural</option>
</select>
</div>
</div>
<div class="form-group" id="categoryGroup">
<label for="title" class="control-label col-sm-3">Category</label>
<div class="input-group col-xs-8" class="" id="categoryList">
<select class="form-control" name="category" id="category">
<option value="" selected></option>
</select>
</div>
</div>
,這裏是我的腳本,它的工作與AJAX調用適當的選項來代替類別選擇菜單:
<script type="text/javascript">
function getCategories(str) {
if (str == "") {
document.getElementById("categoryList").innerHTML = "";
return;
}
if (window.XMLHttpRequest) { // code for IE7+, Firefox, Chrome, Opera, Safari
xmlhttp = new XMLHttpRequest();
} else { // code for IE6, IE5
xmlhttp = new ActiveXObject("Microsoft.XMLHTTP");
}
xmlhttp.onreadystatechange = function() {
if (xmlhttp.readyState == 4 && xmlhttp.status == 200) {
document.getElementById("categoryList").innerHTML = xmlhttp.responseText;
}
}
xmlhttp.open("POST", "getPropertyCategories.php?type=" + str, true);
xmlhttp.send();
}
</script>
我不知道如何更新這也是一類增加了categoryGroup ID