我想驗證電子郵件地址。哪個用戶在我的表格中輸入,但它總是給「請輸入有效的電子郵件地址」錯誤,即使我寫了真正的電子郵件地址。在哪裏,我應該做什麼修正電子郵件模式或如果條件在我的代碼?幫我。爲什麼電子郵件驗證在我的應用程序中總是出錯?
這是我的java文件:
IndividualuserFragment.java:
public View onCreateView(LayoutInflater inflater, @Nullable ViewGroup container, Bundle savedInstanceState) {
View rootview = inflater.inflate(R.layout.fragment_individualuser, container, false);
save = (Button) rootview.findViewById(R.id.save);
cancel = (Button) rootview.findViewById(R.id.cancel);
email = (EditText) rootview.findViewById(R.id.editemail);
password = (EditText) rootview.findViewById(R.id.editpassword);
final String emailPattern = "^[_A-Za-z0-9-]+(\\\\.[_A-Za-z0-9-]+)*@[A-Za-z0-9]+(\\\\.[A-Za-z0-9]+)*(\\\\.[A-Za-z]{2,})$";
fm =getFragmentManager();
cancel.setOnClickListener(new View.OnClickListener(){
@Override
public void onClick(View v) {
fm.beginTransaction().replace(R.id.content_frame,new LoginFragment()).commit();
}
});
save.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
if(!(email.getText().toString().matches(emailPattern) && email.getText().toString().length() > 0)){
email.setError("please valid email address");
email.requestFocus();
}
else if(!(password.getText().toString().length()>=6 && password.getText().toString().length()<=10)){
password.setError("please enter valid password");
password.requestFocus();
}else {
// AsyncTask obj = new AsyncDemo();
// obj.execute();
new myasyncDemo().execute();
}
}
});
return rootview;
}
試試這個.. http://stackoverflow.com/questions/12947620/email-address-validation-in-android-on-edittext –