將對象拖放到容器上並將其標記爲已佔用

我有多個對象和多個容器，我的計劃是任何對象都可以放在任何容器上，但是一旦容器上有一個對象，我想讓它被佔用，不允許有更多的對象。有一個isOcuppied電話或類似的東西，我找不到任何這樣的例子。將對象拖放到容器上並將其標記爲已佔用

local function onTouch(event) 
local t = event.target 

local phase = event.phase 
if "began" == phase then 
    -- Make target the top-most object 
    local parent = t.parent 
    parent:insert(t) 
    display.getCurrentStage():setFocus(t) 


    -- Spurious events can be sent to the target, e.g. the user presses 
    -- elsewhere on the screen and then moves the finger over the target. 
    -- To prevent this, we add this flag. Only when it's true will "move" 
    -- events be sent to the target. 
    t.isFocus = true 

    -- Store initial position 
    t.x0 = event.x - t.x 
    t.y0 = event.y - t.y 
elseif t.isFocus then 
    if "moved" == phase then 
     -- Make object move (we subtract t.x0,t.y0 so that moves are 
     -- relative to initial grab point, rather than object "snapping"). 
     t.xScale = 1.7 
     t.yScale = 1.7 
     t.x = event.x - t.x0 
     t.y = event.y - t.y0 
     --t1 = t1..t.value 
    elseif "ended" == phase or "cancelled" == phase then 
    for i = 1, #posX do 
    if (((t.x >= ((sizeX/2) + posX[i] - ((2/3) * sizeX))) and (t.y >= ((sizeY/2) + posY - ((1/3) * sizeY))) and (t.x <= ((sizeX/2) + posX[i] + ((2/3) * sizeX))) and (t.y <= ((sizeY/2) + posY + ((1/3) * sizeY)))) or ((t.x >= ((sizeX/2) + posX[i] - ((1/3) * sizeX))) and (t.y >= ((sizeY/2) + posY - ((2/3) * sizeY))) and (t.x <= ((sizeX/2) + posX[i] + ((1/3) * sizeX))) and (t.y <= ((sizeY/2) + posY + ((2/3) * sizeY)))) or ((t.x >= ((sizeX/2) + posX[i] - ((1/2) * sizeX))) and (t.y >= ((sizeY/2) + posY - ((1/2) * sizeY))) and (t.x <= ((sizeX/2) + posX[i] + ((1/2) * sizeX))) and (t.y <= ((sizeY/2) + posY + ((1/2) * sizeY))))) then 
     t.x, t.y = posX[i] + (sizeX/2), posY + (sizeY/2); 
    elseif (((t.x >= ((sizeX/2) + posX1[i] - ((2/3) * sizeX))) and (t.y >= ((sizeY/2) + posY1 - ((1/3) * sizeY))) and (t.x <= ((sizeX/2) + posX1[i] + ((2/3) * sizeX))) and (t.y <= ((sizeY/2) + posY1 + ((1/3) * sizeY)))) or ((t.x >= ((sizeX/2) + posX1[i] - ((1/3) * sizeX))) and (t.y >= ((sizeY/2) + posY1 - ((2/3) * sizeY))) and (t.x <= ((sizeX/2) + posX1[i] + ((1/3) * sizeX))) and (t.y <= ((sizeY/2) + posY1 + ((2/3) * sizeY)))) or ((t.x >= ((sizeX/2) + posX1[i] - ((1/2) * sizeX))) and (t.y >= ((sizeY/2) + posY1 - ((1/2) * sizeY))) and (t.x <= ((sizeX/2) + posX1[i] + ((1/2) * sizeX))) and (t.y <= ((sizeY/2) + posY1 + ((1/2) * sizeY))))) then 
     t.x, t.y = posX1[i] + (sizeX/2), posY1 + (sizeY/2); 
     t2[i] = t.value 
     --t1 = t1..t.value 
    -- elseif (((t.x >= ((sizeX/2) + posX2 - ((2/3) * sizeX))) and (t.y >= ((sizeY/2) + posY2 - ((1/3) * sizeY))) and (t.x <= ((sizeX/2) + posX2 + ((2/3) * sizeX))) and (t.y <= ((sizeY/2) + posY2 + ((1/3) * sizeY)))) or ((t.x >= ((sizeX/2) + posX2 - ((1/3) * sizeX))) and (t.y >= ((sizeY/2) + posY2 - ((2/3) * sizeY))) and (t.x <= ((sizeX/2) + posX2 + ((1/3) * sizeX))) and (t.y <= ((sizeY/2) + posY2 + ((2/3) * sizeY)))) or ((t.x >= ((sizeX/2) + posX2 - ((1/2) * sizeX))) and (t.y >= ((sizeY/2) + posY2 - ((1/2) * sizeY))) and (t.x <= ((sizeX/2) + posX2 + ((1/2) * sizeX))) and (t.y <= ((sizeY/2) + posY2 + ((1/2) * sizeY))))) then 
     -- t.x, t.y = posX2 + (sizeX/2), posY2 + (sizeY/2); 
    end 
    end 
     t1 = t1..t.value 
     t.xScale = 1 
     t.yScale = 1 
     --print(tile.label) 
     display.getCurrentStage():setFocus(nil) 
     t.isFocus = false 
     --n = n + 1 
     --value = " " 
    end 
end

這裏是我的代碼，因爲它的立場，也爲Im我有連接到每個瓷磚如磚一=「A」的值，目前我每次只需追加一個字符串瓦片被移動，但我想要字符串或者可以使用一個表格只在瓷磚放入一個容器時才被添加。例如，如果一個字母是在錯誤的地方，我將其移動到我摸到了兩次正確的地方，所以我最終的字符串將是錯誤的

來源

2013-01-07 Gooner

任何人都可以請幫我解決這個問題嗎？我已經正確地閱讀了單詞或短語，現在我需要的是如何阻止在容器中的另一個之上進行拼貼 – Gooner

爲什麼不設置你的容器中的值：

myContainer.isOccupied = false

然後在你的活動處理程序中，當你到達結束階段時，你可以簡單地進行檢查：

if not myContainer.isOccupied then 
    -- code to drop 
    myContainer.isOccupied = true 
end

來源

2013-01-20 21:25:07

將對象拖放到容器上並將其標記爲已佔用

回答

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