第二週,我嘗試鏈接apollo-server-express/MongoDB/Mongoose/GraphQL堆棧中的兩個集合,但我不明白。我發現了一個與REST API相似的課程,我需要的是所謂的關係。我需要這個,但在GraphQL關係GraphQL
如何車添加到用戶? 我收集的測試服務器,該代碼是在這裏:https://github.com/gHashTag/test-graphql-server 幫助
第二週,我嘗試鏈接apollo-server-express/MongoDB/Mongoose/GraphQL堆棧中的兩個集合,但我不明白。我發現了一個與REST API相似的課程,我需要的是所謂的關係。我需要這個,但在GraphQL關係GraphQL
如何車添加到用戶? 我收集的測試服務器,該代碼是在這裏:https://github.com/gHashTag/test-graphql-server 幫助
我克隆了你的項目,並實現了一些代碼,這裏我改變了關係的作品。請注意,我只是做了一個基本的代碼,沒有驗證或提前dataloader只是爲了確保非複雜性。希望它可以幫助。
的src/graphql /解析器/轎廂resolvers.js
import Car from '../../models/Car'
import User from '../../models/User'
export default {
getCar: (_, { _id }) => Car.findById(_id),
getCars:() => Car.find({}),
getCarsByUser: (user, {}) => Car.find({seller: user._id }), // for relationship
createCar: async (_, args) => {
// Create new car
return await Car.create(args)
}
}
的src/graphql /分解器/用戶resolvers.js
import User from '../../models/User'
export default {
getUser: (_, { _id }) => User.findById(_id),
getUsers:() => User.find({}),
getUserByCar: (car, args) => User.findById(car.seller), // for relationship
createUser: (_, args) => {
return User.create(args)
}
}
的src/graphql /解析器/index.js
import UserResolvers from './user-resolvers'
import CarResolvers from './car-resolvers'
export default {
User:{
cars: CarResolvers.getCarsByUser // tricky part to link query relation ship between User and Car
},
Car:{
seller: UserResolvers.getUserByCar // tricky part to link query relation ship between User and Car
},
Query: {
getUser: UserResolvers.getUser,
getUsers: UserResolvers.getUsers,
getCar: CarResolvers.getCar,
getCars: CarResolvers.getCars
},
Mutation: {
createUser: UserResolvers.createUser,
createCar: CarResolvers.createCar,
}
}
的src/graphql/schema.js
export default`
type Status {
message: String!
}
type User {
_id: ID!
firstName: String
lastName: String
email: String
cars: [Car]
}
type Car {
_id: ID
make: String
model: String
year: String
seller: User
}
type Query {
getUser(_id: ID!): User
getUsers: [User]
getCar(_id: ID!): Car
getCars: [Car]
}
type Mutation {
createUser(firstName: String, lastName: String, email: String): User
// change from _id to seller, due to base on logic _id conflict with CarId
createCar(seller: ID!, make: String, model: String, year: String): Car
}
schema {
query: Query
mutation: Mutation
}
`
的src/middlewares.js
import bodyParser from 'body-parser'
import { graphqlExpress, graphiqlExpress } from 'apollo-server-express'
import { makeExecutableSchema } from 'graphql-tools'
import typeDefs from '../graphql/schema'
import resolvers from '../graphql/resolvers'
import constants from './constants'
export const schema = makeExecutableSchema({
typeDefs,
resolvers
})
export default app => {
app.use('/graphiql', graphiqlExpress({
endpointURL: constants.GRAPHQL_PATH
}))
app.use(
constants.GRAPHQL_PATH,
bodyParser.json(),
graphqlExpress(req => ({
schema,
context: {
event: req.event
}
}))
)
}
嘗試做這樣的事情在你的車解析器
export default {
getCar: ({ _id: ownId }, { _id }) =>
Car.findById(ownId || _id);
// here is the rest of your code
您需要在用戶類型添加一個解析器爲cars
場。
const resolvers = {
Query: {
getUsers: ...
getCars: ...
...
},
Mutation: {
...
},
User: {
cars: ...
}
}
非常感謝您,表瞭解一對多通信,但如何使連接多對多? –