參數化測試很適合將不同數據輸入到您的測試中。但是,我創建了一個示例計算器,我想爲其創建參數化測試。但是,我發現您只能爲單個測試創建一組參數化數據。使用多個測試進行參數化junit測試
我已經創建了參數化測試,用於在預期結果中添加2個數字。由於預期結果不同,這些數據將不會與減法一起使用。
是否有可能對每個測試的參數化數據進行加,減,乘和除?
非常感謝您的任何建議,
@RunWith(Parameterized.class)
public class CalculatorModelPresenterTest {
private CalculatorModel mCalculatorModel;
/* Array of tests */
@Parameterized.Parameters
public static Collection<Object[]> data() {
return Arrays.asList(new Object[][]{
{3.0, 4.0, 7.0},
{4.0, 3.0, 7.0},
{8.0, 2.0, 10.0},
{-1.0, 4.0, 3.0},
{3256.0, 4.0, 3260.0}
});
}
private double mNumberOne;
private double mNumberTwo;
private double mExpectedResult;
/* CONSTRUCTOR THAT ASSIGNS THE FIELDS WITH THE TEST DATA */
public CalculatorModelPresenterTest(double numberOne, double numberTwo, double expectedResult) {
mNumberOne = numberOne;
mNumberTwo = numberTwo;
mExpectedResult = expectedResult;
}
/* THIS TEST WILL PASS AS THE TEST DATA IS FOR ADDING */
@Test
public void testAdd() throws Exception {
final double actualResult = mCalculatorModel.add(mNumberOne, mNumberTwo);
assertEquals(actualResult, mExpectedResult, 0);
}
/* HOWEVER, THIS TEST WILL ALWAYS FAIL AS THE TEST DATA IS CUSTOMIZED FOR THE ADD */
@Test
public void testSub() throws Exception {
final double actualResult = mCalculatorModel.sub(mNumberOne, mNumberTwo);
assertEquals(actualResult, mExpectedResult, 0);
}
@Before
public void setUp() throws Exception {
mCalculatorModel = new CalculatorModel();
}
@After
public void tearDown() throws Exception {
mCalculatorModel = null;
}
}
你並不需要設置'mCalculatorModel'到'null'在'tearDown'方法,因爲JUnit的每一組參數創建類'CalculatorModelPresenterTest'的新實例。 –