我正在編程一個應用程序,它應該去一個按鈕按下另一個視圖控制器,但相反,它崩潰時,我運行它。編輯器顯示:並帶有編輯器突出顯示:但在控制檯中沒有錯誤。 Here is the code for the viewcontroller that does the segue: //
// DoTodayViewController.swift
// Paley Foundation: Starfish
我有一個UIpicker模態窗口。一切工作正常,除了一件事。當用戶單擊輸入文本字段時,帶有UIpickerView的模式窗口按預期打開。如果所選的行是正確的,並且用戶單擊確定按鈕,則當前代碼無法註冊該值。 // Set the default row, so if user click ok without changing it is recorded
self.picker.selectRo
This is NOT a duplicate of In Swift, how can I declare a variable of a specific type that conforms to one or more protocols? . This question is about a specific use case where I needed a metatype and
我從CocoaPods安裝Google地圖SDK後出現此錯誤。 CoreData: annotation: Failed to load optimized model at path '/Users/nabeel/Library/Developer/CoreSimulator/Devices/96078737-8063-4BC1-97DB-7FECEC6835D9/data/Containers