如何將每個文本文件行分隔爲單獨的列表？

Question

說我有一個包含以下內容的文本文件：

Bob 15 M 
John 16 M 
Jen 15 F 

我如何把它變成一個列表，該列表值：

listOne = ['Bob', '15', 'M'] 
listTwo = ['John', '16', 'M'] 
listThree = ['Jen', '15', 'F'] 

感謝

Answer 1

只是拆分它並將其解壓縮

bob, john, jen = [a.split() for a in open(file)] 

Answer 2

用打開文件和分割（）：

with open('text.txt') as f: 
    strings = f.readlines() 
    data = [string.split() for string in strings] 

Answer 3

with open('text.txt') as file: 
    lines = file.readlines()  # Creates a list of lines 
    for line in lines: 
     line = line.split()   # Split each line into list of "words" 

這給你一個嵌套列表這可能是明智的。如果你迫切想3所列出，使用此：

evalvar = "" 
count = 0 
for line in lines: 
    count += 1 
    evalvar += "list"+str(count)+" = "+str(line)+";" 
exec(evalvar)           # Runs the evalvar which has 
                 # code in it. 

Answer 4

您可以在文件中適用string.split每一行：

import string 

with open('text.txt') as text: 
    result = map(string.split, text) 

使用Python 3，您需要兌現的map，否則文件沒有按之前它關閉「噸得到閱讀：

result = list(map(string.split, text)) 

然而，string.split已被廢棄，只適用於str對象，正ot unicode。一個更普遍的解決方案是創建一個列表理解：

result = [line.split() for line in text]