<form action="<?php $_SERVER['PHP_SELF'] ?>" method="POST">
<input type="text" name="duration" placeholder="Enter duration">
<input type="text" name="budget" placeholder="Enter Budget">
<input type="text" name="keyskills" placeholder="Enter Skills">
<input type="text" name="jobdescription" placeholder="Enter Job Description">
<input type="text" name="edate" placeholder="Click to enter expiry date">
<input type="text" name="cdexmin" placeholder="Enter Minimum Experience">
<input type="text" name="cdexmax" placeholder="Enter Maximum Experience">
<input type="submit">
</form>
<?php
if(isset($_POST['submit'])) {
try {
// Establish server connection and select database
$username = $_SESSION['username'];
$stmt = $db->prepare("SELECT * FROM employer INNER JOIN company ON employer.cid = company.cid WHERE employer.username='$username' ");
$stmt->execute();
$row = $stmt->fetch(PDO::FETCH_ASSOC);
$cid=$row['cid'];
$eid = $row['eid'];
$duration = $_POST['duration'];
$budget = $_POST['budget'];
$keyskills = $_POST['keyskills'];
$jobdescription = $_POST['jobdescription'];
$edate = $_POST['edate'];
$cdexmin = $_POST['cdexmin'];
$cdexmax = $_POST['cdexmax'];
$stmt = $db->prepare("INSERT INTO job(cid,eid,duration,budget,keyskills,jdesc,edate,cdexmin,cdexmax) values('$cid','$eid','$duration','$budget','$keyskills','$jobdescription','$edate','$cdexmin','$cdexmax') ");
$stmt->execute();
echo "JOB POSTED SUCCESSFULLY";
} catch(PDOException $e) {
echo "Error occurs:". $e->getMessage();
}
}
?>
以下是我剛剛爲試圖將值插入數據庫的示例表單創建的代碼。我的問題是這些值沒有進入數據庫。表單提交不會將數據輸入到數據庫中
爲什麼它不起作用?有沒有我找不到的語法錯誤?
頁面解析很容易完成,它不會顯示任何錯誤,但值不會進入數據庫。
爲您的提交按鈕添加一個'name'標籤。 ''input type =「submit」name =「submit」>' –
您應該驗證所有用戶提交的數據,並且由於您沒有正確使用準備好的語句而容易受到SQL注入攻擊 – SpacePhoenix
請注意,代碼'< ?php'_SERVER ['PHP_SELF']?>'在'form'的'action'屬性中並不實際回顯任何內容,導致'action =「」'。這是有效的,因爲空字符串表示當前頁面,但您應該將其更改爲'<?= $ _ SERVER ['PHP_SELF'];?>'。 – Antti29