2014-09-29 101 views
0

我想繞過Android的基本身份驗證,並陷入了這個錯誤。 請參閱下面我的代碼:MalformedChallengeException:身份驗證的挑戰是空的

HttpUriRequest request = new HttpGet(url); 
String credentials = "username" + ":" + "password"; 
String base64EncodedCredentials = Base64.encodeToString(credentials.getBytes(), Base64.NO_WRAP); 
request.addHeader("Authorization", "Basic " + base64EncodedCredentials); 

HttpClient httpclient = new DefaultHttpClient(); 

try { 
HttpResponse response = httpclient.execute(request); 
Log.d("Login: Response", EntityUtils.toString(response.getEntity())); 
} catch (IOException e) { 
e.printStackTrace(); 
} 

這是我得到的錯誤..

09-29 12:01:21.990: W/System.err(3438): org.apache.http.client.ClientProtocolException 
09-29 12:01:21.990: W/System.err(3438):  at org.apache.http.impl.client.AbstractHttpClient.execute(AbstractHttpClient.java:672) 
09-29 12:01:21.990: W/System.err(3438):  at org.apache.http.impl.client.AbstractHttpClient.execute(AbstractHttpClient.java:509) 
09-29 12:01:21.990: W/System.err(3438):  at org.apache.http.impl.client.AbstractHttpClient.execute(AbstractHttpClient.java:487) 
09-29 12:01:21.990: W/System.err(3438):  at com.accenture.emsmobile.backend.LoginAsyncTask.doInBackground(LoginAsyncTask.java:33) 
09-29 12:01:22.000: W/System.err(3438):  at com.accenture.emsmobile.backend.LoginAsyncTask.doInBackground(LoginAsyncTask.java:1) 
09-29 12:01:22.000: W/System.err(3438):  at android.os.AsyncTask$2.call(AsyncTask.java:287) 
09-29 12:01:22.000: W/System.err(3438):  at java.util.concurrent.FutureTask.run(FutureTask.java:234) 
09-29 12:01:22.000: W/System.err(3438):  at android.os.AsyncTask$SerialExecutor$1.run(AsyncTask.java:230) 
09-29 12:01:22.000: W/System.err(3438):  at java.util.concurrent.ThreadPoolExecutor.runWorker(ThreadPoolExecutor.java:1080) 
09-29 12:01:22.000: W/System.err(3438):  at java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:573) 
09-29 12:01:22.010: W/System.err(3438):  at java.lang.Thread.run(Thread.java:841) 
09-29 12:01:22.010: W/System.err(3438): Caused by: org.apache.http.auth.MalformedChallengeException: Authentication challenge is empty 
09-29 12:01:22.020: W/System.err(3438):  at org.apache.http.impl.auth.RFC2617Scheme.parseChallenge(RFC2617Scheme.java:72) 
09-29 12:01:22.020: W/System.err(3438):  at org.apache.http.impl.auth.AuthSchemeBase.processChallenge(AuthSchemeBase.java:111) 
09-29 12:01:22.030: W/System.err(3438):  at org.apache.http.impl.auth.BasicScheme.processChallenge(BasicScheme.java:95) 
09-29 12:01:22.030: W/System.err(3438):  at org.apache.http.impl.client.DefaultRequestDirector.processChallenges(DefaultRequestDirector.java:1068) 
09-29 12:01:22.030: W/System.err(3438):  at org.apache.http.impl.client.DefaultRequestDirector.handleResponse(DefaultRequestDirector.java:965) 
09-29 12:01:22.030: W/System.err(3438):  at org.apache.http.impl.client.DefaultRequestDirector.execute(DefaultRequestDirector.java:475) 
09-29 12:01:22.030: W/System.err(3438):  at org.apache.http.impl.client.AbstractHttpClient.execute(AbstractHttpClient.java:670) 
09-29 12:01:22.030: W/System.err(3438):  ... 10 more 
+0

請點擊此鏈接: http://stackoverflow.com/questions/3283 234/http-basic-authentication-in-java-using-httpclient – prakash 2014-09-29 04:17:48

+0

試過這些,仍然沒有發現認證挑戰。 – user142020a 2014-09-29 04:41:43

+0

如果用戶名和密碼正確,它正在工作,但在憑證錯誤時引發異常。 – user142020a 2014-09-29 05:13:22

回答

0

替換:

request.addHeader("Authorization", "Basic " + base64EncodedCredentials); 

有了:

request.addHeader("Authorization", "Basic "+Base64.encodeToString("rat#1:rat".getBytes(),Base64.NO_WRAP)); 
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