獲得連續3天

我試圖使用從該查詢SO質疑Check for x consecutive days - given timestamps in database計算大量的連續天用戶提交的活性，即3天，5天，7天等獲得連續3天

查詢是：

SELECT IF(COUNT(1) > 0, 1, 0) AS has_consec 
FROM 
(
SELECT * 
FROM 
(
    SELECT IF(b.dateAdded IS NULL, @val:[email protected]+1, @val) AS consec_set 
    FROM activity a 
    CROSS JOIN (SELECT @val:=0) var_init 
    LEFT JOIN activity b ON 
     a.userID = b.userID AND 
     a.dateAdded = b.dateAdded + INTERVAL 1 DAY 
    WHERE a.userID = 1 
) a 
GROUP BY a.consec_set 
HAVING COUNT(1) >= 3 
) a

當日期字段不是dateTime但代碼如何修改代碼以忽略dateTime的時間組件？我曾嘗試使用DATE（dateAdded），但沒有奏效。

我的數據是這樣的：

userID dateAdded 
1  2016-07-01 17:01:56 
1  2016-07-02 12:45:49 
1  2016-07-03 13:06:27 
1  2016-07-04 12:51:10 
1  2016-07-05 15:51:10 
2  2016-07-06 16:51:10 
2  2016-07-07 11:51:10 
1  2016-07-08 11:26:38

感謝

來源

2016-07-12 puks1978

嘗試此http： //www.tutorialspoint.com/mysql/mysql-date-time-functions.htm#function_timestampadd –

嘗試將您的日期時間字段設置爲日期，就像這個'DATE（a.dateAdded）' – 1000111

試過了，它不起作用。如果我將時間組件更改爲相同的查詢工作，但即使投射到DATE也沒有產生正確的結果。 – puks1978

鑄造的dateAdded場Date。

請給它一個嘗試，讓我知道這是否解決了問題：

SELECT IF(COUNT(1) > 0, 1, 0) AS has_consec 
FROM 
(
SELECT * 
FROM 
(
    SELECT IF(b.dateAdded IS NULL, @val:[email protected]+1, @val) AS consec_set 
    FROM activity a 
    CROSS JOIN (SELECT @val:=0) var_init 
    LEFT JOIN activity b ON 
     a.userID = b.userID AND 
     DATE(a.dateAdded) = DATE(b.dateAdded) + INTERVAL 1 DAY 
    WHERE a.userID = 1 
) a 
GROUP BY a.consec_set 
HAVING COUNT(1) >= 3 
) a;

注：使用timestamp將返回正確的輸出只有當他們有相同time (hh:mm:ss)

來源

2016-07-12 05:29:05 1000111

回答

相關問題