暗號嵌套收集查詢不正確地聚集

Question

我想執行這個查詢

MATCH (p:Person)-->(s:Startup) 
WITH DISTINCT p 
MATCH (p)-->(s:Startup)-->(m:Market) 
WITH DISTINCT p, s, m, COLLECT(m) as markets 
ORDER BY id(s) 
RETURN DISTINCT p, COUNT(DISTINCT s) as inv, 
       COLLECT({id: id(s), markets: markets}) as startups, 
       count (m) as mctotal 
ORDER BY inv DESC 
LIMIT 10 

，但我想不出爲什麼它不聚集與他們的市場正確創業公司。 這是我查詢的結果：

+-----+-----+------------+---------+ 
| p | inv | startups | mctotal | 
+-----+-----+------------+---------+ 
| p | 11 | id: 1  | 7 | 
|  |  | markets: 1 |   | 
|  |  |   |   | 
|  |  | id: 1  |   | 
|  |  | markets: 2 |   | 
|  |  |   |   | 
|  |  | id: 2  |   | 
|  |  | markets: 3 |   | 
|  |  |   |   | 
|  |  | id: 2  |   | 
|  |  | markets: 4 |   | 

...等等。

，我想獲得的結果如下：

+-----+-----+---------------+---------+ 
| p | inv | startups  | mctotal | 
+-----+-----+---------------+---------+ 
| p | 11 | id: 1   | 7 | 
|  |  | markets:[1,2] |   | 
|  |  |    |   | 
|  |  | id: 2   |   | 
|  |  | markets:[3,4] |   | 

我希望這是清楚我所要求的。

Answer 1

1. 不要使用與聚合不同
2. 不聚集您返回簡單值（這是你的主要問題）相同的值
3. 不匹配兩次

這裏是一個應該更好的變體，你沒有分享你的樣品圖，所以我不能嘗試它

MATCH (p)-->(s:Startup)-->(m:Market) 
WITH p, s, COLLECT(m) as markets, count(m) as mcount 
ORDER BY id(s) 
RETURN p, COUNT(DISTINCT s) as inv, 
      COLLECT({id: id(s), markets: markets}) as startups, 
      sum(mcount) as mctotal 
ORDER BY inv DESC 
LIMIT 10