從1個密碼查詢中的幾個關係中提取權重

Question

我想根據用戶查看或更新文件的次數來計算特定用戶的「公司索引」。爲了得到這個，我將賦值給特定的路徑。這是一個例子：

(u1:User {name: 'Alice'})-[:UPDATED]->(f:File)<-[:VIEWED]-(u2:User) // is worth 0.2 points 
(u1:User {name: 'Alice'})-[:VIEWED]->(f:File)<-[:VIEWED]-(u2:User) // is worth 0.1 points 
(u1:User {name: 'Alice'})-[:VIEWED]->(f:File)<-[:UDATED]-(u2:User) // is worth 0.2 points 
(u1:User {name: 'Alice'})-[:UPDATED]->(f:File)<-[:UPDATED]-(u2:User) // is worth 0.5 points 

該圖顯示了一個可能的圖。

我想知道查詢是如何看起來像返回以下結果。

User: Alice, User: Charly, index: (3 * 0.2) // 3 because there are 3 matching paths (Relationship with the lowest weight in the path) 
User: Alice, User: Bob, index: (3 * 0.1) 

這是我到目前爲止有：

MATCH (u1:User {name:'Alice'})-[r1:VIEWED]->(f:File)<-[r2:UPDATED]-(u2:User) 
OPTIONAL MATCH (u1:User {name:'Alice'})-[r3:VIEWED]->(f:File)<-[r4:VIEWED]-(u3:User) 
RETURN u2.name, min(r1.weight) AS ViewUpd, u3.name, min(r3.weight) AS ViewView 

該查詢根本不能工作，但我希望它澄清我想要什麼。

Answer 1

[編輯]

此查詢是否做你想要的？

MATCH (u1:User { name:'Alice' })-[r1]->(f:File)<-[r2]-(u2:User) 
RETURN 
    u2.name AS name, 
    SUM(
    r1.weight * (CASE 
     WHEN (TYPE(r1)= "VIEWED" AND TYPE(r2)= "VIEWED") THEN 0.1 
     WHEN (TYPE(r1)= "UPDATED" AND TYPE(r2)= "UPDATED") THEN 0.5 
     ELSE 0.2 
     END)) AS index; 

Here is a console顯示此查詢，這裏是一個示例的結果：

+--------------------------------+ 
| name  | index    | 
+--------------------------------+ 
| "Bob"  | 0.6000000000000001 | 
| "Elvis" | 1.5    | 
| "David" | 0.6000000000000001 | 
| "Charley" | 2.1    | 
+--------------------------------+ 

在我的樣本數據，「查理」有UPDATED關係，並與File通過「是UPDATED一個VIEWED關係愛麗絲」。 Charley產生的index是這兩種關係的索引值的總和。