由於某種原因,我的銀行腳本無法正常工作。更具體地說,search()
不起作用。我有點理解爲什麼它沒有,可能是因爲if(obj.returnId() == n)
,但我不知道如何解決它。當我搜索一個帳戶時,它只會讓我找到最後一個帳戶,而不是以前的帳戶。這裏是我的代碼:銀行系統不工作
#include "stdafx.h"
#include <iostream>
#include <string>
#include <string.h>
#include <fstream>
#include <Windows.h>
#include <conio.h>
using namespace std;
bool loop = true;
class account
{
int id;
char name[40];
char password[40];
public:
void getData()
{
cout << "\nEnter your name: ";
cin >> name;
cout << "\nEnter ID: ";
cin >> id;
cout << "\Enter pass: ";
cin >> password;
}
void showData()
{
cout << "\nName: ";
puts(name);
cout << "\nID: " << id;
cout << "\n";
}
int returnId()
{
return id;
}
};
void createAccount()
{
account obj;
ofstream fileCreate;
fileCreate.open("accounts.dat", ios::binary|ios::app);
obj.getData();
fileCreate.write((char*)&obj,sizeof(obj));
fileCreate.close();
}
void display()
{
account obj;
ifstream fileRead;
fileRead.open("accounts.dat", ios::binary);
while(fileRead.read((char*)&obj, sizeof(obj)))
{
obj.showData();
}
fileRead.close();
}
void search(int n)
{
account obj;
ifstream fileRead;
fileRead.open("accounts.dat", ios::binary);
while(fileRead.read((char *) &obj, sizeof(obj)));
{
fileRead.seekg(0,ios::beg);
if(obj.returnId() == n)
{
obj.showData();
}
else {
cout << "\nUser not foud!\n";
}
}
fileRead.close();
}
void main()
{
cout << "Welcome to the Bank.\n\n";
while (loop==true)
{
char choice[10];
cout << "Please select an option:\n";
cout << "------------------------------------------------\n";
cout << "(a)Log into an account\n(b)Create an account\n(s)Search an account\n(e)Exit\n";
cout << "------------------------------------------------\n";
cout << "Choice: ";
cin >> choice;
choice[0] = tolower(choice[0]);
cout << "\n------------------------------------------------\n\n";
switch (choice[0])
{
case 'a':
display();
break;
case 's':
int n;
cout << "Enter the ID of the account: ";
cin >> n;
search(n);
break;
case 'b':
createAccount();
break;
case 'e':
loop = false;
break;
default:
system("CLS");
cout << "The option \"" << choice[0] << "\" is invalid.\n\n\n\n";
break;
}
};
cout << "\n\n\n";
cout << "Click anything to exit.";
getch();
}
保存這樣的類非常脆弱,並且由於函數指針和vTables的原因,它可能無法正確讀回。改爲使用正確的序列化庫。 –
另外,'n'是一個角色嗎?如果是這樣的話:試試這個:'if(obj.returnId()=='n')' – Annabelle
你可能已經從這個例子中刪除了很多代碼,但仍然產生了錯誤。下次請嘗試發佈一個最簡單的例子。 – Beta