在java中的httppost後處理響應

Question

我使用httpclient在java中發佈xml。我也期待一個XML的迴應。 如何解析xml的響應？

這是我迄今爲止

HttpClient cliet = HttpClientFactory.getClient("mhurl.com"); 
... 
PostMethod post; 
post.setRquestEntity(new StringRequestEntity(myxml_in_string,"xml",...); 
... 
int result = client.executeMethod(post); 
InputStream in = post.getRespoinseBodyAsStream(); 
?? //Not sure how to handle the response from here 

感謝。

Answer 1

標準Java DOM API：

DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance(); 
DocumentBuilder db = dbf.newDocumentBuilder(); 
Document doc = db.parse(in); 

最後一行是至關重要的。

SAX API

SAXParserFactory factory = SAXParserFactory.newInstance(); 
SAXParser saxParser = factory.newSAXParser(); 
saxParser.parse(in, yourCustomCallback); 

JAXB

假設你有合適的模型：

JAXBContext context = JAXBContext.newInstance(Response.class); 
Response response = (Response)context.createUnmarshaller().unmarshal(in);