我發現了很多文章,描述瞭如何將一組XML元素解組爲一個HashMap,只要它們在「父」元素內。但是,我沒有得到這與直接根源下的孩子一起工作!JAXB將XML元素解組爲HashMap
選項1 - 作品:
<?xml version="1.0" encoding="UTF-8"?>
<checks>
<checks>
<check key="check1"/>
<check key="check2"/>
...
</checks>
</checks>
選擇2 - 難道不工作:
<?xml version="1.0" encoding="UTF-8"?>
<checks>
<check key="check1"/>
<check key="check2"/>
...
</checks>
檢查:
package com.foo.conf;
import java.util.Map;
import javax.xml.bind.annotation.XmlElement;
import javax.xml.bind.annotation.XmlRootElement;
import javax.xml.bind.annotation.adapters.XmlJavaTypeAdapter;
@XmlRootElement(name="checks")
public class Checks {
@XmlJavaTypeAdapter(ChecksAdapter.class)
@XmlElement(name="checks")
public Map<String, Check> checkMap;
}
檢查:
package com.foo.conf;
import javax.xml.bind.annotation.XmlAttribute;
import javax.xml.bind.annotation.XmlValue;
public class Check {
@XmlAttribute public String key;
@XmlValue public String description;
public Check() { }
public Check(String key) {
this.key = key;
}
public String getCheckKey() {
return this.key;
}
}
CheckMapType:
package com.foo.conf;
import java.util.List;
import javax.xml.bind.annotation.XmlElement;
class CheckMapType {
@XmlElement(name="check")
public List<Check> checkList; // = new ArrayList<Check>();
}
ChecksAdapter:
package com.foo.conf;
import java.util.HashMap;
import java.util.Map;
import javax.xml.bind.annotation.adapters.XmlAdapter;
final class ChecksAdapter extends XmlAdapter<CheckMapType, Map<String, Check>> {
@Override
public CheckMapType marshal(Map<String, Check> arg0) throws Exception {
return null;
}
@Override
public Map<String, Check> unmarshal(CheckMapType arg0) throws Exception {
System.out.println("u: " + arg0.checkList.size());
Map<String, Check> map = new HashMap<String, Check>();
for (Check check : arg0.checkList) {
System.out.println(check);
map.put(check.key, check);
}
return map;
}
}
這是(一些虛擬測試線)我如何生成類/調用解組:
JAXBContext jc = JAXBContext.newInstance(Checks.class);
Unmarshaller u = jc.createUnmarshaller();
Checks c = (Checks) u.unmarshal(new File("checks.xml"));
System.out.println(c.checkMap.size());
任何想法關於如何讓選項#2工作?它使用List而不是Map來工作,但我需要HashMap,因爲我必須通過給定的鍵訪問對象...
任何提示非常感謝!
感謝您提供非常有用的解釋 - 我會很快嘗試。 – rawberto