0
上午使用時間選擇器通過對話框片段。在那個時間選擇器設置最小和最大time.i時,我得到了堆棧溢出錯誤,當我點擊減號(現在的時間以分鐘爲單位的最小值)按鈕分鐘時間選擇器API 10,但在API 15中,其工作fine.am無法得到解決這個問題。任何人都知道可以幫助我解決這個問題。Android中的Timepicker中的Stackoverflow錯誤?
時間選擇對話框片段類
package data.picker;
import java.text.DateFormat;
import android.app.Dialog;
import android.app.TimePickerDialog;
import android.app.TimePickerDialog.OnTimeSetListener;
import android.os.Bundle;
import android.support.v4.app.DialogFragment;
import android.widget.TimePicker;
public class Time_picker extends DialogFragment{
OnTimeSetListener ontimeSet;
int minHour;
int minMinute;
private int maxHour = 24;
private int maxMinute =00;
DateFormat dateFormat;
public Time_picker() {
}
public void setCallBack(OnTimeSetListener ontime) {
ontimeSet = ontime;
}
private int hours, minutes;
@Override
public void setArguments(Bundle args) {
super.setArguments(args);
hours = args.getInt("hours");
minutes = args.getInt("minute");
minHour = hours;
minMinute = minutes;
}
@Override
public Dialog onCreateDialog(Bundle savedInstanceState) {
TimePickerDialog _time = new TimePickerDialog(getActivity(), ontimeSet, hours, minutes,false){
@Override
public void onTimeChanged(TimePicker view, int hourOfDay, int minute) {
// TODO Auto-generated method stub
try{
boolean validTime;
if(hourOfDay < minHour) {
validTime = false;
}
else if(hourOfDay == minHour) {
validTime = minute >= minMinute;
}
else if(hourOfDay == maxHour) {
validTime = minute <= maxMinute;
}
else {
validTime = true;
}
if(validTime) {
hours = hourOfDay;
minutes = minute;
}
else {
updateTime(hours, minutes);
}
}catch(Exception e){
}
}
};
return _time;
}
}
登錄貓錯誤
如何使用該條件更新時間選取器。 – Yugesh