XML-RPC異常從執行到執行異步切換

Question

我有以下XML-RPC實現工作，我從apache website中複製並稍作修改。

public class DemoServer { 
    public static void main (String [] args) { 
    try { 
     WebServer webServer = new WebServer(8080); 
     XmlRpcServer xmlRpcServer = webServer.getXmlRpcServer(); 

     PropertyHandlerMapping phm = new PropertyHandlerMapping(); 
     phm.addHandler("sample", RequestHandler.class); 
     xmlRpcServer.setHandlerMapping(phm); 

     XmlRpcServerConfigImpl serverConfig = 
       (XmlRpcServerConfigImpl) xmlRpcServer.getConfig(); 
     serverConfig.setEnabledForExtensions(true); 
     serverConfig.setContentLengthOptional(false); 

     webServer.start(); 
    } catch (Exception e) { 
     e.printStackTrace(); 
    } 
    } 
} 

隨着客戶端：

public class DemoClient { 
    public static void main (String[] args) { 
    try { 
     XmlRpcClientConfigImpl config = new XmlRpcClientConfigImpl(); 
     config.setServerURL(new URL("http://127.0.0.1:8080/xmlrpc")); 
     config.setEnabledForExtensions(true); 
     config.setConnectionTimeout(60 * 1000); 
     config.setReplyTimeout(60 * 1000); 

     XmlRpcClient client = new XmlRpcClient(); 

     // set configuration 
     client.setConfig(config); 

     // make the a regular call 
     Object[] params = new Object[] { new Integer(2), new Integer(3) }; 

        //!CRITICAL LINE! 
     Integer result = (Integer) client.execute("sample.sum", params); 

     System.out.println("2 + 3 = " + result); 
    } catch (Exception e) { 
     e.printStackTrace(); 
    } 
    } 
} 

我首先運行demoServer的，然後我運行DemoClient，和它打印 「2 + 3 = 5」。 但是，如果我改變

Integer result = (Integer) client.execute("sample.sum", params); 

到

client.executeAsync("sample.sum", params, new ClientCallback()); 

然後我得到以下幾點：

In error 
java.lang.ExceptionInInitializerError 
    at java.lang.Runtime.addShutdownHook(Runtime.java:192) 
at java.util.logging.LogManager.<init>(LogManager.java:237) 
at java.util.logging.LogManager$1.run(LogManager.java:177) 
at java.security.AccessController.doPrivileged(Native Method) 
at java.util.logging.LogManager.<clinit>(LogManager.java:158) 
at java.util.logging.Logger.getLogger(Logger.java:273) 
at sun.net.www.protocol.http.HttpURLConnection.<clinit>(HttpURLConnection.java:62) 
at sun.net.www.protocol.http.Handler.openConnection(Handler.java:44) 
at sun.net.www.protocol.http.Handler.openConnection(Handler.java:39) 
at java.net.URL.openConnection(URL.java:945) 
at org.apache.xmlrpc.client.XmlRpcSun15HttpTransport.newURLConnection(XmlRpcSun15HttpTransport.java:62) 
at org.apache.xmlrpc.client.XmlRpcSunHttpTransport.sendRequest(XmlRpcSunHttpTransport.java:62) 
at org.apache.xmlrpc.client.XmlRpcClientWorker$1.run(XmlRpcClientWorker.java:80) 
at java.lang.Thread.run(Thread.java:680) 
Caused by: java.lang.IllegalStateException: Shutdown in progress 
at java.lang.Shutdown.add(Shutdown.java:62) 
at java.lang.ApplicationShutdownHooks.<clinit>(ApplicationShutdownHooks.java:21) 
... 14 more 

我ClientCallback類：

public class ClientCallback implements AsyncCallback { 

@Override 
public void handleError(XmlRpcRequest request, Throwable t) { 
    System.out.println("In error"); 
    t.printStackTrace(); 

} 

@Override 
public void handleResult(XmlRpcRequest request, Object result) { 
    System.out.println("In result"); 
    System.out.println(request.getMethodName() + ": " + result); 
} 
} 

這是怎麼回事錯在這裏？我正在使用Apache XML-RPC版本3.1.2，不幸的是我發現的示例代碼在版本2.x中，並且不再適用。另外我從類的開始處省略了導入語句（確實沒有語法錯誤）。任何幫助將非常感激。

Answer 1

您的主程序正在運行結束，因爲executeAsync立即返回而不等待請求被髮送或響應返回。

你想通過使用executeAsync來完成什麼？