Tensorflow + Keras + Convolution2d：類型錯誤：「詮釋」對象不是可調用

Question

我跑一下CNN的代碼在我的機器，但它得到了一個錯誤的反饋。

我的代碼片段：

model.add(Convolution2D(4 ,3 ,5, 5, border_mode='valid' ,input_shape=(200,200,3))) 

，我也嘗試：

model.add(Convolution2D(4 ,3 ,5, 5, border_mode='valid' ,input_shape=(3,200,200))) 

和錯誤是：

Traceback (most recent call last): 
    File "", line 1, in 
    File "/Users/liumengyang/anaconda/lib/python3.5/site-packages/spyder/utils/site/sitecustomize.py", line 866, in runfile 
    execfile(filename, namespace) 
    File "/Users/liumengyang/anaconda/lib/python3.5/site-packages/spyder/utils/site/sitecustomize.py", line 102, in execfile 
    exec(compile(f.read(), filename, 'exec'), namespace) 
    File "/Users/liumengyang/Desktop/visual/pre-processing.py", line 61, in 
    model.add(Convolution2D(4 ,3 ,5, 5, border_mode='valid' ,input_shape=(200,200,3))) 
    File "/Users/liumengyang/anaconda/lib/python3.5/site-packages/keras/models.py", line 280, in add 
    layer.create_input_layer(batch_input_shape, input_dtype) 
    File "/Users/liumengyang/anaconda/lib/python3.5/site-packages/keras/engine/topology.py", line 370, in create_input_layer 
    self(x) 
    File "/Users/liumengyang/anaconda/lib/python3.5/site-packages/keras/engine/topology.py", line 487, in __call__ 
    self.build(input_shapes[0]) 
    File "/Users/liumengyang/anaconda/lib/python3.5/site-packages/keras/layers/convolutional.py", line 410, in build 
    self.W = self.init(self.W_shape, name='{}_W'.format(self.name)) 
TypeError: 'int' object is not callable 

如何解決這個問題呢？

Answer 1

我想，也許你感到困惑與tensorflow的語法。

。在你的說法，model.add(Convolution2D(4 ,3 ,5, 5, border_mode='valid' ,input_shape=(200,200,3)))一些錯字，

試試這個model.add(Convolution2D(4 ,5, 5, border_mode='valid' ,input_shape=(200,200,3)))如果你想有4個過濾器，其尺寸爲5×5。