2011-12-15 28 views
2

我剛從http://www.epx.com.br/pysctp/安裝了pysctp,並且無法正常工作。我可能做錯了什麼?如何開始使用Python SCTP堆棧(pysctp)?

我在Red Hat Linux上。

Python 2.7.2 (default, Oct 25 2011, 10:11:43) 
[GCC 4.1.2 20070626 (Red Hat 4.1.2-14)] on linux2 
Type "help", "copyright", "credits" or "license" for more information. 
>>> import socket 
>>> import sctp 
>>> sk = sctp.sctpsocket_tcp(socket.AF_INET) 
Traceback (most recent call last): 
    File "<stdin>", line 1, in <module> 
    File "/usr/local/python2.7/lib/python2.7/site-packages/sctp.py", line 1644, in __init__ 
    sctpsocket.__init__(self, family, TCP_STYLE, sk) 
    File "/usr/local/python2.7/lib/python2.7/site-packages/sctp.py", line 1016, in __init__ 
    self.events = event_subscribe(self) 
    File "/usr/local/python2.7/lib/python2.7/site-packages/sctp.py", line 623, in __init__ 
    self.__dict__.update(self.container._get_events()) 
    File "/usr/local/python2.7/lib/python2.7/site-packages/sctp.py", line 1356, in _get_events 
    return _sctp.get_events(self._sk.fileno()) 
IOError: [Errno 22] Invalid argument 

回答

2

有人打破了ABI(增加了幾個字段來結構sctp_event_subscribe,內核希望用戶空間想要新的數量)。這裏是一個kludge,適當的修復將是內核接受已經被編譯爲具有較小struct_event_subscribe的頭的舊應用程序,並且不給它們新的字段...)。甚至更新到lksctp-devel中的新樣式頭並重新編譯所有內容。

--- _sctp.c~ 2011-12-20 16:48:45.000000000 +0200 
+++ _sctp.c 2011-12-20 16:49:23.498912252 +0200 
@@ -832,8 +832,9 @@ 
{ 
    PyObject* ret = 0; 
    int fd; 
+ char padding[4]; // Happily overflowing here... 
    struct sctp_event_subscribe v; 
- socklen_t lv = sizeof(v); 
+ socklen_t lv = 10; // Come to think of it, it could have been 9 at some point 

    if (PyArg_ParseTuple(args, "i", &fd)) { 
     if (getsockopt(fd, SOL_SCTP, SCTP_EVENTS, &v, &lv)) { 
1

看起來像pysctp的內部錯誤。 get_events調用getsockopt

getsockopt(2)說:

EINVAL optlen invalid in setsockopt(). 
1

布萊恩的權利 - 有某種問題,呼籲getsockopt爲SCTP_EVENTS的。我一直沒能解決這個問題,但我已經在sctp.py註釋掉這一行:

self.__dict__.update(self.container._get_events()) 

的SCTP套接字然後似乎很好地工作。我還沒有需要獲得SCTP_EVENTS,所以現在很好。