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我正在創建一個應用程序來拉我的朋友YouTube的飼料。當我運行應用程序,我收到一個錯誤:Youtube ios feed thumbnail
2013-03-30 16:34:04.973 eastcoastdyes[15395:c07] *** Terminating app due to uncaught exception 'NSInvalidArgumentException', reason: '*** -[NSURL initWithString:relativeToURL:]: nil string parameter'
*** First throw call stack:
(0x1a38012 0x1354e7e 0x1a37deb 0xd4a49d 0xdc11e4 0x3859 0x3538fb 0x3539cf 0x33c1bb 0x34cb4b 0x2e92dd 0x13686b0 0x3014fc0 0x300933c 0x3009150 0x2f870bc 0x2f88227 0x2f888e2 0x1a00afe 0x1a00a3d 0x19de7c2 0x19ddf44 0x19dde1b 0x19927e3 0x1992668 0x298ffc 0x231d 0x2245 0x1)
libc++abi.dylib: terminate called throwing an exception
(lldb)
這裏是我的代碼:
- (UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath {
static NSString *cellID = @"Cell Identifier";
UITableViewCell *cell = [tableView dequeueReusableCellWithIdentifier:cellID];
if (!cell) {
cell = [[UITableViewCell alloc] initWithStyle:UITableViewCellStyleSubtitle reuseIdentifier:cellID];
}
NSDictionary *video = [self.videos objectAtIndex:indexPath.row];
cell.textLabel.text = [video objectForKey:@"title"];
cell.detailTextLabel.text = [video objectForKey:@"uploader"];
NSURL *url = [[NSURL alloc] initWithString:[video objectForKey:@"data.items.thumbnail.hqdefault"]];
[cell.imageView setImageWithURL:url placeholderImage:[UIImage imageNamed:@"placeholder"]];
return cell;
}
我接受它在NSURL * URL ...幫助請
爲什麼它返回一個零對象? –
您的密鑰要麼不正確,要麼沒有爲該密鑰設置字符串。 – Alec
你不能,我再說一遍,不能用'key paths'和-objectForKey :.它根本無法工作。如果您必須使用關鍵路徑而不是多個「-objectForKey:」調用,請改用「-valueForKeyPath:」。 –