指針到虛擬成員函數

Question

考慮下面的代碼

class BASE 
{ 
    public: 
      virtual void test_f(){std::cout<<"BASE::test_f\n";} 
}; 

class DERIVED:public BASE 
{ 
    public: 
      virtual void test_f(){std::cout<<"DERIVED::test_f\n";} 
}; 

void (BASE::*p_base)() = &BASE::test_f; 

p_base是一個指針，指向類的成員函數，但它是多態的。 這意味着，

DERIVED a; 
(a.*p_base)(); 

將打印衍生:: TEST_F

我怎麼能得到的指針的基類的TEST_F使非多態的電話嗎？

Answer 1

使用std::mem_fun：http://en.cppreference.com/w/cpp/utility/functional/mem_fn

例子：

DERIVED a; 
f = mem_fun(&BASE::test_f); 
f(a); // calls BASE's test_f with a pointer to a as the "this" pointer