2013-04-05 92 views
4

我有可能包含引號,\,/,\ r \ n中的NSString,我想將其轉換爲一個JSON編碼字符串,字符串這樣Objective-C - 如何將NSString轉換爲轉義的JSON字符串?

"text1\text2"

成爲

\"text1\\text2\"

有沒有現有的功能讓我這樣做?

此外,我在我的項目中使用SBJson,但我無法找到SBJson是否可以做到這一點。

NSJSONSerialization是上不了檯面的,因爲我的應用程序仍然需要支持OSX 10.6

回答

11

這是否回答你的問題?

-(NSString *)JSONString:(NSString *)aString { 
    NSMutableString *s = [NSMutableString stringWithString:aString]; 
    [s replaceOccurrencesOfString:@"\"" withString:@"\\\"" options:NSCaseInsensitiveSearch range:NSMakeRange(0, [s length])]; 
    [s replaceOccurrencesOfString:@"/" withString:@"\\/" options:NSCaseInsensitiveSearch range:NSMakeRange(0, [s length])]; 
    [s replaceOccurrencesOfString:@"\n" withString:@"\\n" options:NSCaseInsensitiveSearch range:NSMakeRange(0, [s length])]; 
    [s replaceOccurrencesOfString:@"\b" withString:@"\\b" options:NSCaseInsensitiveSearch range:NSMakeRange(0, [s length])]; 
    [s replaceOccurrencesOfString:@"\f" withString:@"\\f" options:NSCaseInsensitiveSearch range:NSMakeRange(0, [s length])]; 
    [s replaceOccurrencesOfString:@"\r" withString:@"\\r" options:NSCaseInsensitiveSearch range:NSMakeRange(0, [s length])]; 
    [s replaceOccurrencesOfString:@"\t" withString:@"\\t" options:NSCaseInsensitiveSearch range:NSMakeRange(0, [s length])]; 
    return [NSString stringWithString:s]; 
} 

來源:converting NSString to JSON string

+0

怎麼樣幾行代碼用於轉義不可打印的字符? '\ U1234'等 – 2013-04-05 21:12:27

+0

是否正確處理了unicode字符? (http://json.org) – Jean 2013-04-05 21:15:38

+0

是的。謝謝! – lakeskysea 2013-04-05 21:41:28

0

夫特2:

/// Escape reserved characters to produce a valid JSON String 
/// For example double quotes `"` are replaced by `\"` 
/// - parameters: 
/// - String: an unescaped string 
/// - returns: valid escaped JSON string 
func JSONString(str: String?) -> String? { 
    var result : String? = nil 
    if let str = str { 
     result = str 
      .stringByReplacingOccurrencesOfString("\"", withString: "\\\"", options: .CaseInsensitiveSearch) 
      .stringByReplacingOccurrencesOfString("/", withString: "\\/", options: .CaseInsensitiveSearch) 
      .stringByReplacingOccurrencesOfString("\n", withString: "\\n", options: .CaseInsensitiveSearch) 
      .stringByReplacingOccurrencesOfString("\u{8}", withString: "\\b", options: .CaseInsensitiveSearch) 
      .stringByReplacingOccurrencesOfString("\u{12}", withString: "\\f", options: .CaseInsensitiveSearch) 
      .stringByReplacingOccurrencesOfString("\r", withString: "\\r", options: .CaseInsensitiveSearch) 
      .stringByReplacingOccurrencesOfString("\t", withString: "\\t", options: .CaseInsensitiveSearch) 
    } 
    return result 
} 

夫特3:

func JSONString(str: String) -> String { 
    var result = str 
    result = result.replacingOccurrences(of: "\"", with: "\\\"") 
     .replacingOccurrences(of: "/", with: "\\/") 
     .replacingOccurrences(of: "\n", with: "\\n") 
     .replacingOccurrences(of: "\u{8}", with: "\\b") 
     .replacingOccurrences(of: "\u{12}", with: "\\f") 
     .replacingOccurrences(of: "\r", with: "\\r") 
     .replacingOccurrences(of: "\t", with: "\\t") 

    return result 
} 

非常有用的,以防止錯誤:Domain=NSCocoaErrorDomain Code=3840 "Invalid escape sequence around character 123."

+0

不應該'\ n'替換爲'\\ n'? – Crashalot 2016-10-27 21:15:36

1

讓我們做更多的原生JSON的路;)

如果妳喜歡我的回答,請明星我在https://github.com/wanjochan

//trick: id(@[s]) => string => trim [] => target 
//NSString *s 
s=[[NSString alloc] initWithData: 
    [NSJSONSerialization dataWithJSONObject:@[s] options:0 error:nil] 
    encoding:NSUTF8StringEncoding]; 
s=[[s substringToIndex:([s length]-1)] substringFromIndex:1]; 
0

斯威夫特4解決方案

extension String { 
    var stringEncodedJSON: String { 
     var copy = self 
     let encodingDict: [String: String] = ["\"": "\\\"", "/": "\\/", "\n": "\\n", "\u{8}": "\\b","\u{12}": "\\f", "\r": "\\r", "\t": "\\t"] 
     encodingDict.forEach({ copy = copy.replacingOccurrences(of: $0, with: $1) }) 
     return copy 
    } 
}