2015-11-12 65 views
0

正在爲我的C++類處理任務,並且出現標題中提到的錯誤。我知道這並不值得繼續,但我認爲這可能是我如何稱呼我的功能的問題。我的代碼如下。獲取「向量下標超出範圍」錯誤

主營:

#include <iostream> 
#include <vector> 
#include "VectorHeader.h" 
using namespace std; 
int main() 
{ 
int items, num, sum, min, max, avg; 
vector<int> v; 

cout << "How many items would you like in this vector?" << endl; 
cin >> items; 

/* After the user enters his numbers, the for loop will enter those numbers into the vector */ 
cout << "Please enter the numbers you would like in the vector." << endl; 
for (int ii = 0; ii < items; ii++) 
{ 
    cin >> num; 
    v.push_back(num); 
} 

/* This block prints the vector neatly by checking for when the last number in the vector appears */ 
cout << "Your vector = <"; 
for (int ii = 0; ii < v.size(); ++ii) 
{ 
    if (ii < v.size()-1) 
     cout << v[ii] << ", "; 
    else 
     cout << v[ii]; 
} 
cout << ">" << endl; 

sum = Sum(v); 
min = Min(v); 
max = Max(v); 
avg = Average(v); 

cout << "The sum of your vector = " << sum << endl; 
cout << "The min of your vector = " << min << endl; 
cout << "The max of your vector = " << max << endl; 
cout << "The average of your vector = " << avg << endl; 

return 0; 
} 

功能:

#include <iostream> 
#include <vector> 
#include "VectorHeader.h" 
using namespace std; 

int Sum(vector<int> &v) 
{ 
int sum = 0; 
for (int ii = 0; ii < v.size(); ii++) // For loop for finding the sum of the  vector 
{ 
    sum += v[ii]; 
} 

return sum; 
} 

int Min(vector<int> &v) 
{ 
int min; 
for (int ii = 0; ii < v.size(); ii++) // Runs through the vector setting the  new min to 'min' each time it finds one 
{ 
    if (v[ii] < v[ii + 1]) 
     min = v[ii]; 
} 
return min; 
} 

int Max(vector<int> &v) 
{ 
int max; 
for (int ii = 0; ii < v.size(); ii++) // Runs through the vector setting the  new max to 'max' each time it finds one 
{ 
    if (v[ii] > v[ii + 1]) 
     max = v[ii]; 
} 
return max; 
} 

int Average(vector<int> &v) 
{ 
int avg, sum = 0; 
for (int ii = 0; ii < v.size(); ii++) // For loop for finding the sum of the vector 
{ 
    sum += v[ii]; 
} 
avg = sum/v.size(); // Then divide the sum by the number of vector items to find the average 

return avg; 
    } 

最後,頭文件:

#include <iostream> 
#include <vector> 
using namespace std; 

int Sum(vector<int> &v); 
int Min(vector<int> &v); 
int Max(vector<int> &v); 
int Average(vector<int> &v); 
+0

你試過調試你的程序嗎? – antiguru

+0

是的,我得到的唯一信息是「表達式:向量下標超出範圍」 – Sean

+0

這個表達式將會是一個問題:'v [ii + 1])'因爲'i'在給定範圍內:'for (int ii = 0; ii lurker

回答

1

罪魁禍首是ii + 1 - 當iiv.size() - 1它在矢量之外。

將您的邊界條件更改爲v.size() - 1

1

在您的MIN()和MAX()函數,你用v[ii+1],當ii == v.size() - 1;時超出範圍。

+0

我發佈後不久就看到了,謝謝您的確認! – Sean