一個字符串轉換爲文本行的文本區域內部在PHP

Question

從題目本身相比，我需要一個字符串比較一個textarea裏面的文本行。

這裏的輸出我從PHP接到了，我有計劃，用於打印的可用設備我的Linux服務器，我把它放在一個文本里。

Device --------------  |  NAme  ------------------- |  Status 

/dev/ttyS0-----------| Profilic |-------------------|Available 

/dev/ttyUSB0 -------| Test | ---------------------|Busy 

現在我有設備陣列..

$devices = array("/dev/ttyS0", "/dev/ttyUSB0", "/dev/ttyUSB1"); 

現在，我怎麼比較我的字符串數組，如果存在於文本區域下面的設備？

說，如果在textarea的發現/dev/ttyS0然後，因爲我在字符串數組具有的/ dev/ttyS0來返回true。

示例代碼如何獲取輸出從Linux到PHP。

echo "<textarea>"; 
echo stream_get_contents($pipes[1]); 
echo "</textarea>"; 

我想發生。（樣機代碼）

if(/dev/ttyS0 == in the textarea){ 
    enable this part of code 
} 

if(/dev/ttyUSB0 == in the textarea){ 
    enable this part of code 
} 

and so on.... 

我該怎麼辦呢？..

Answer 1

假設你的設備描述符應在textarea的行開始通過您的格式出現以上，您可以迭代線路並查找strpos($line, $device) === 0。

$lines = explode("\n", $teextarea_content); 
// loop over array of device descriptors 
// and make an array of those found in the textarea 
$found_devices = array(); 
foreach ($devices as $device) { 
    // Iterate over lines in the textarea 
    foreach ($lines as $line) { 
    if (strpos($line, $device) === 0) { 
     // And add the device to your array if found, then break 
     // out of the inner loop 
     $found_devices[] = $device; 
     break; 
    } 
    } 
} 
// These are the devices you found... 
var_dump($found_devices); 

// Finally, enable your blocks. 
if (in_array("/dev/ttyUSB0", $found_devices)) { 
    // enable for /dev/ttyUSB0 
} 
// do the same for your other devices as necessary 

// OR... You could use a fancy switch in a loop to act on each of the found devices 
// Useful if two or more of them require the same action. 
foreach ($found_devices as $fd) { 
    switch($fd) { 
    case '/dev/ttyUSB0': 
     // stuff for this device 
     break; 
    case '/dev/ttyS0': 
     // stuff for this device 
     break; 
    // These two need the same action so use a fallthrough 
    case '/dev/ttyS1': 
    case '/dev/ttyS2': 
     // Stuff for these two... 
     break; 
    } 
} 

Answer 2

您很可能希望使用AJAX做到這一點... JQuery使得AJAX非常簡單。

，但你的PHP會想看看沿線的東西...

<?php 
// Already assuming you have filled out your array with devices... 
$dev = $_POST["device"]; 


// This will loop through all of your devices and check if one matched the input. 
foreach($devices as $device) { 
    if ($device == $dev) { 
     // Whatever you want to do if the device matches. 
    } 
} 
?> 

乾杯