2017-04-12 20 views
0

我只希望我的AlertDialog在滿足某些條件時(當給出的名稱和姓氏有效時)被解僱 - 否則它應始終位於父視圖的頂部。我的代碼是這樣的:AlertDialog與LinearLayout不應該關閉按鈕單擊

final AlertDialog.Builder alert = new AlertDialog.Builder(this); 
    final TextView instructions = new TextView(this); 
    instructions.setText(R.string.alert_enter_data); 
    final EditText name = new EditText(this); 
    name.setHint(R.string.name); 
    final EditText surname = new EditText(this); 
    surname.setHint(R.string.surname); 
    LinearLayout ll=new LinearLayout(this); 
    ll.setOrientation(LinearLayout.VERTICAL); 
    ll.addView(instructions); 
    ll.addView(name); 
    ll.addView(surname); 
    alert.setView(ll); 
    alert.setNeutralButton(R.string.enter, new DialogInterface.OnClickListener() { 
     public void onClick(DialogInterface dialog, int whichButton) { 
      String name_txt = name.getText().toString(); 
      String surname_txt = surname.getText().toString(); 
      if ((name_txt.length() > 1) && (surname_txt.length() > 1)) { 
       dialog.dismiss(); 
      } 
     } 
    }); 
    final AlertDialog alert_dialog = alert.create(); 
    alert_dialog.setCanceledOnTouchOutside(false); 
    alert_dialog.show(); 

這段代碼的AlertDialog按下按鈕時消失,不管輸入文字。然後我試了這個:

alert_dialog.setOnShowListener(new DialogInterface.OnShowListener() { 

    @Override 
    public void onShow(DialogInterface dialog) { 

     Button b = alert.getButton(AlertDialog.BUTTON_POSITIVE); 
     b.setOnClickListener(new View.OnClickListener() { 

      @Override 
      public void onClick(View view) { 
       String name_txt = name.getText().toString(); 
       String surname_txt = surname.getText().toString(); 
       String email_txt = email.getText().toString(); 
       String cellphone_txt = cellphone.getText().toString(); 
       String postcode_txt = postcode.getText().toString(); 
       if ((name_txt.length() > 1) && (surname_txt.length() > 1) && (email_txt.length() > 4)) { 
        if (debug_mode) {Log.i(TAG,"clause 1");} 
        String data_to_upload = name_txt + ", " + surname_txt + ", " + email_txt + ", "+ cellphone_txt + ", " + postcode_txt + "\n"; 
        // upload_to_github(data_to_upload); 
        alert_dialog.dismiss(); 
       } 
      } 
     }); 
    } 
}); 

但是這樣我得到的不是按鈕。警報對話框只包含EditText字段。

+0

你看過這裏嗎?:http://stackoverflow.com/a/27345656/2910520。您需要重寫按鈕偵聽器,以防止AlertDialog在選擇單擊時使用'dialog.getButton(AlertDialog.BUTTON_POSITIVE).setOnClickListener(...)'關閉自身。你可以刪除showListener,因爲它是沒有必要的,在修改按鈕監聽器 – MatPag

+0

之前,你需要'create()'和'show()'對話框,這就是我在第二個代碼片段中做的事情,但是這樣我根本沒有得到任何按鈕 - 我估計是因爲我使用了「LinearLayout」,但我在這裏輸了。 –

回答

1
alert.setNeutralButton(R.string.enter, new DialogInterface.OnClickListener() { 

Button b = alert.getButton(AlertDialog.BUTTON_POSITIVE); 

兩者都是不同的按鈕。

嘗試

鍵b = alert.getButton(AlertDialog.BUTTON_NEUTRAL);