錯誤號：1064

Question

我在codeigniter中加入兩個表時遇到此錯誤。

Error Number: 1064 

You have an error in your SQL syntax; check the manual that 
corresponds to your MariaDB server version for the right syntax to use 
near '.`id = a`.`assignee_key where a`.`assigned_to="office" and 
user`.`id="53"`' at line 1 

select a`.* from address as `a LEFT JOIN user ON user`.`id = a`.`assignee_key where a`.`assigned_to="office" and user`.`id="53" 

$this->db->select('select a.* from address as a LEFT JOIN user ON user.id = a.assignee_key where a.assigned_to="office" and user.id="'.$user_id.'"'); 
$query = $this->db->get(); 
return $query->row(); 

Answer 1

你有別名錶名的問題。試試這個

$this->db->select('select a.* from address a LEFT JOIN user u ON u.id = a.assignee_key where a.assigned_to="office" and u.id="'.$user_id.'"'); 
$query = $this->db->get(); 
return $query->row(); 

Answer 2

你有兩個選擇。這是您的查詢的更好/結構化版本。

$this->db->select("a.*") 
      ->from("address as a") 
      ->join("user","user.id = a.assignee_key","left") 
      ->where(array("a.assigned_to"=>"office","user.id"=>$user_id));   
    $query = $this->db->get(); 
    return $query->row(); 

更新：對於評論儘量左外連接

->join("user","user.id = a.assignee_key","left outer") 

它保留了不匹配的行從第一個（左）表中，第二個形狀以空行加入他們（右）表。