用第二個數組中的值替換第一個數組中的字符串

Question

由於某種原因，我正在爲此苦苦掙扎。

我有以下2個數組，我需要從$ IMG陣列取數組值，爲了將它們插入到$文本數組，附加/更換％IMG_標籤，就像這樣：

$text = array(
    0 => "Bunch of text %img_ %img_: Some more text blabla %img_", 
    1 => "More text %img_ blabla %img_" 
); 

$img = array("BLACK","GREEN","BLUE", "RED", "PINK"); 

我希望我的$文本數組落得像這樣：

$text = array(
    0 => "Bunch of text %img_BLACK %img_GREEN: Some moretext blabla %img_BLUE", 
    1 => "More text %img_RED blabla %img_PINK" 
); 

注：$ IMG數組中的項目數會有所不同，但將永遠是一樣的％IMG_在$文本數陣列。

Answer 1

這裏有一種方法，你可以做到這一點，利用preg_replace_callback帶班包裹跟蹤的細節在$ IMG陣列替換字符串中使用哪種：

class Replacer 
{ 
    public function __construct($img) 
    { 
     $this->img=$img; 
    } 

    private function callback($str) 
    { 
     //this function must return the replacement string 
     //for each match - we simply cycle through the 
     //available elements of $this->img. 

     return '%img_'.$this->img[$this->imgIndex++]; 
    } 

    public function replace(&$array) 
    { 
     $this->imgIndex=0; 

     foreach($array as $idx=>$str) 
     { 
      $array[$idx]=preg_replace_callback(
       '/%img_/', 
       array($this, 'callback'), 
       $str); 
     } 
    } 
} 

//here's how you would use it with your given data 
$r=new Replacer($img); 
$r->replace($text); 

Answer 2

OOP是好的。這是我的非OOP之一：D

$text = array(
    0 => "Bunch of text %img_ %img_: Some more text blabla %img_", 
    1 => "More text %img_ blabla %img_" 
); 

$img = array("BLACK","GREEN","BLUE", "RED", "PINK"); 

$newtext = array(); 
$k = 0; 
$count = count($text); 
for($i = 0; $i < $count; $i++) { 
    $texts = split("%img_", $text[$i]); 
    $jtext = $texts[0]; 
    $subcount = count($texts); 
    for($j = 1; $j < $subcount; $j++) { 
     $jtext .= "%img_"; 
     $jtext .= $img[$k++]; 
     $jtext .= $texts[$j]; 
    } 
    $newtext[] = "$jtext\n"; 
} 

print_r($newtext); 

如果你喜歡，你可以將它分組到一個函數。

希望這會有所幫助。

Answer 3

這裏的另一種方式：

<?php 

$text = array(
    0 => "Bunch of text %img_ %img_: Some more text blabla %img_", 
    1 => "More text %img_ blabla %img_" 
); 

$img = array("BLACK","GREEN","BLUE", "RED", "PINK"); 

foreach ($text as &$row) { 
     $row = str_replace("%img_", "%%img_%s", $row); 
     $row = vsprintf($row, $img); 
} 

print_r($text); 

，輸出：

Array 
(
    [0] => Bunch of text %img_BLACK %img_GREEN: Some more text blabla %img_BLUE 
    [1] => More text %img_BLACK blabla %img_GREEN 
) 

Answer 4

另一個版本的PHP 5.3+使用anonymous function和一些spl：

$text = array(
    "Bunch of text %img_ %img_: Some more text blabla %img_", 
    "More text %img_ blabla %img_" 
); 
$img = new ArrayIterator(array("BLACK","GREEN","BLUE", "RED", "PINK")); 
foreach($text as &$t) { 
    $t = preg_replace_callback('/%img_/', function($s) use($img) { 
     $rv = '%img_' . $img->current(); 
     $img->next(); 
     return $rv; 
    }, $t); 
} 

var_dump($text);