我想在我的android應用程序中使用API(首選爲Google地圖,如果支持的話)以傳遞位置的經度/緯度並且API返回城市名稱。傳遞lon/lat和返回城市名稱的API
在解決這個,你應該去getAddressLine(x)的
我想在我的android應用程序中使用API(首選爲Google地圖,如果支持的話)以傳遞位置的經度/緯度並且API返回城市名稱。傳遞lon/lat和返回城市名稱的API
在解決這個,你應該去getAddressLine(x)的
我相信API是速率的限制。即在一個小時內您不能多次訪問該API。Android包含一個Geocoder類,它也具有ReverseGeocoding功能。請看this link。
請求什麼Geonames.org是另一回事。下面是一個示例API調用來找到西雅圖附近的名字: http://api.geonames.org/citiesJSON?north=47.65&south=47.55&east=-122.30&west=-122.40&lang=de&username=demo
{
"geonames": [
{
"fcodeName": "seat of a second-order administrative division",
"countrycode": "US",
"fcl": "P",
"fclName": "city, village,...",
"name": "Seattle",
"wikipedia": "",
"lng": -122.3320708,
"fcode": "PPLA2",
"geonameId": 5809844,
"lat": 47.6062095,
"population": 608660
},
{
"fcodeName": "populated place",
"countrycode": "US",
"fcl": "P",
"fclName": "city, village,...",
"name": "Yesler Terrace",
"wikipedia": "",
"lng": -122.3159591,
"fcode": "PPL",
"geonameId": 5816674,
"lat": 47.6009318,
"population": 0
},
{
"fcodeName": "section of populated place",
"countrycode": "US",
"fcl": "P",
"fclName": "city, village,...",
"name": "North Broadway",
"wikipedia": "",
"lng": -122.3204044,
"fcode": "PPLX",
"geonameId": 5804929,
"lat": 47.6462094,
"population": 0
},
{
"fcodeName": "populated place",
"countrycode": "US",
"fcl": "P",
"fclName": "city, village,...",
"name": "Capitol Hill",
"wikipedia": "",
"lng": -122.3195706,
"fcode": "PPL",
"geonameId": 5789123,
"lat": 47.6234317,
"population": 0
},
{
"fcodeName": "populated place",
"countrycode": "US",
"fcl": "P",
"fclName": "city, village,...",
"name": "Interbay",
"wikipedia": "",
"lng": -122.3959623,
"fcode": "PPL",
"geonameId": 5798384,
"lat": 47.641209,
"population": 0
},
{
"fcodeName": "populated place",
"countrycode": "US",
"fcl": "P",
"fclName": "city, village,...",
"name": "Ross (historical)",
"wikipedia": "",
"lng": -122.3623502,
"fcode": "PPL",
"geonameId": 5808844,
"lat": 47.6478758,
"population": 0
},
{
"fcodeName": "populated place",
"countrycode": "US",
"fcl": "P",
"fclName": "city, village,...",
"name": "Stevens",
"wikipedia": "",
"lng": -122.3066667,
"fcode": "PPL",
"geonameId": 7153940,
"lat": 47.6297222,
"population": 0
},
{
"fcodeName": "section of populated place",
"countrycode": "US",
"fcl": "P",
"fclName": "city, village,...",
"name": "Belltown",
"wikipedia": "",
"lng": -122.3509605,
"fcode": "PPLX",
"geonameId": 5786913,
"lat": 47.6164871,
"population": 0
},
{
"fcodeName": "populated place",
"countrycode": "US",
"fcl": "P",
"fclName": "city, village,...",
"name": "Queen Anne",
"wikipedia": "",
"lng": -122.366239,
"fcode": "PPL",
"geonameId": 5807648,
"lat": 47.6359314,
"population": 0
},
{
"fcodeName": "populated place",
"countrycode": "US",
"fcl": "P",
"fclName": "city, village,...",
"name": "South Seattle",
"wikipedia": "",
"lng": -122.312903,
"fcode": "PPL",
"geonameId": 5811509,
"lat": 47.5614876,
"population": 0
}
]
}
謝謝,我認爲這是我需要的。我現在要測試它。 – mohamede1945
我測試過了,但我無法使用它來獲取城市。你知道一個辦法嗎? – mohamede1945
您需要在清單中擁有互聯網許可。 Geocoder geocoder = new Geocoder(this,Locale.getDefault()); 列表
addresses = geocoder.getFromLocation(lat,lng,1); addresses.get(0).getLocality();'地點應該給你這座城市。 – Varun