無限循環在搖滾紙剪刀循環遊戲

Question

我目前正在努力實現while循環在我的遊戲中，因爲它總是給我一個無限循環。我們的想法是繼續比賽，除了只有當用戶鍵入「-1」

// declare variables 
    int player, computer; 
    int counter = 0; 
    // player input 
    System.out.println("Rock, Paper, Scissors!"); 
    System.out.print("Enter 0 for paper, 1 for Scissors, or 2 for Rock (-1 to quit) : "); 
    player = sc.nextInt(); 
    while (player != -1) { 

     // switch statement for player 
     switch (player) { 
     case 0: 
      System.out.println("Player picks Paper"); 
      break; 
     case 1: 
      System.out.println("Player picks Scissors"); 
      break; 
     case 2: 
      System.out.println("Player picks Rock"); 
      break; 
     case -1: 
      System.exit(-1); 
      break; 
     default: 
      System.out.println("Invalid input"); 
     } 

     // generate a random number for computer 
     Random randomGen = new Random(); 
     computer = randomGen.nextInt(3); 

     // switch statement for computer 
     switch (computer) { 
     case 0: 
      System.out.println("Computer picks Paper"); 
      break; 
     case 1: 
      System.out.println("Computer picks Scissors"); 
      break; 
     case 2: 
      System.out.println("Computer picks Rock"); 
      break; 
     default: 
     } 

     // output for each condition 
     if (player == 2 && computer == 1) 
      System.out.println("Player Wins!"); 
     else if (player == 1 && computer == 0) 
      System.out.println("Player Wins!"); 
     else if (player == 0 && computer == 2) 
      System.out.println("Player Wins!"); 
     else if (computer == 1 && player == 0) 
      System.out.println("Computer Wins!"); 
     else if (player == 0 && computer == 2) 
      System.out.println("Computer Wins!"); 
     else if (player == 1 && computer == 2) 
      System.out.println("Computer Wins!"); 
     else 
      System.out.println("Draw"); 
     sc.close(); 
    } 

Answer 1

你永遠不更新player值。將player = sc.nextInt()添加到循環體的末尾。 或者，這樣做

int player; 
while ((player = sc.nextInt()) != -1) { 

而，我相信你也應該刪除調用sc.close();