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我花了半天的時間瘋狂地讓我的澤西服務接受並操縱JSON。將JSON發佈到澤西島請求
下面是我在做什麼: 在PHP中使用Zend Framework:
$client = new Zend_Http_Client("http://localhost:8080/api/");
$data = array("city"=> "Paris", "zip" => "1111");
$json = json_encode($data);
$client->setHeaders("Content-type", "application/json");
$client->setRawData($json, 'application/json')->request("GET");
API方法:
@GET
@Produces(MediaType.APPLICATION_JSON)
@Consumes(MediaType.APPLICATION_JSON)
public Response getAPI(Address addr) {
JSONObject out = new JSONObject();
out.put("city test",addr.getCity());
Response response = null;
return response.ok(out.toString()).header("Accept", "application/json").build();
}
在一個單獨的文件,我有我的註解類:
import javax.xml.bind.annotation.XmlAccessType;
import javax.xml.bind.annotation.XmlAccessorType;
import javax.xml.bind.annotation.XmlElement;
import javax.xml.bind.annotation.XmlRootElement;
@XmlRootElement
public class Address
{
@XmlElement(name="city")
public String city;
@XmlElement(name="zip")
public String zip;
public String getCity() {
return city;
}
}
我收到不受支持的媒體類型錯誤:
Zend_Http_Response Object
(
[version:protected] => 1.1
[code:protected] => 415
[message:protected] => Unsupported Media Type
[headers:protected] => Array
(
[Server] => Apache-Coyote/1.1
[Content-type] => text/html;charset=utf-8
[Content-length] => 1117
[Date] => Tue, 29 May 2012 17:55:03 GMT
[Connection] => close
)
[body:protected] =>
我錯過了什麼?
謝謝大家, 丹尼爾
感謝您的回答,除了輸出,我想我的問題是在輸入中獲取json。這正是我努力實現的目標! – Daniele
只要你的json輸入結構正確,你應該全部設置。編組和解組是爲你完成的。如果它不起作用,請嘗試添加城市/郵編的設置方法,但我不確定是否需要它們。另外,我假設你在服務類中正確設置了@Path? –