User @RamblinRose指出我在EEPROM寫入和讀取的方向,我不知道這是可能的。這解決了我的問題。這裏是所有來這裏想要更全面的答案的人的完整代碼:
#include <DS3231.h>
#include <EEPROM.h>
// Init the DS3231 using the hardware interface
DS3231 rtc(SDA, SCL);
Time t;
bool active = false;
void setup()
{
// Setup Serial connection
Serial.begin(115200);
// Initialize the rtc object
rtc.begin();
pinMode(12, OUTPUT);
pinMode(11, INPUT_PULLUP);
// The following lines can be uncommented to set the date and time
// rtc.setDOW(MONDAY); // Set Day-of-Week to SUNDAY
// rtc.setTime(15, 51, 0); // Set the time to 12:00:00 (24hr format)
rtc.setDate(14, 9, 2017); // Set the date to January 1st, 2014
}
int blinker(int state = 1) {
if(state == 1) {
if (active == true) {
digitalWrite(12, HIGH); // turn the LED on (HIGH is the voltage level)
delay(500); // wait for a second
digitalWrite(12, LOW); // turn the LED off by making the voltage LOW
delay(500);
buttonCheck();
}
}
}
int buttonCheck() {
if(digitalRead(11) == 0) {
active = false;
blinker(0);
}
}
void loop()
{
t = rtc.getTime();
int hour = t.hour;
int min = t.min;
int sec = t.sec;
// // Send time to serial monitor (for debugging)
// Serial.print(hour);
// Serial.print(":");
// Serial.print(min);
// Serial.println(" ");
// Put there different timers in here for demo purposes
// Set activation time
if(hour == 13 && min == 31 && sec == 00) {
if(EEPROM.read(0) == 0) {
active = true;
EEPROM.write(0, 1);
Serial.println("Not run recently, activating");
} else {
active = false;
EEPROM.write(0, 0);
Serial.println("Run recently, skipping this one");
}
}
if(hour == 13 && min == 35 && sec == 00) {
if(EEPROM.read(0) == 0) {
active = true;
EEPROM.write(0, 1);
Serial.println("Not run recently, activating");
} else {
active = false;
EEPROM.write(0, 0);
Serial.println("Run recently, skipping this one");
}
}
if(hour == 13 && min == 45 && sec == 00) {
if(EEPROM.read(0) == 0) {
active = true;
EEPROM.write(0, 1);
Serial.println("Not run recently, activating");
} else {
active = false;
EEPROM.write(0, 0);
Serial.println("Run recently, skipping this one");
}
}
blinker();
delay(1000);
}
是否有一個原因,你不能使用eeprom來存儲某些狀態來跳轉限制?似乎會避開電力損失問題。 – RamblinRose
我確定沒有理由。我只是對這些東西不夠了解,不知道我能做到。謝謝,這可能是完美的解決方案:) –