哨兵循環執行在c

Question

我有下面的代碼，我希望它在進入哨兵號碼後只能打破一次，但此刻我必須輸入兩次哨兵號碼來破解代碼。有任何想法嗎？

#include <stdio.h>// Include a standard C Library 
#define Sentinel_Numb -1 
int main(){ 

    int ID[360];    
    float seconds[360]; 
    int i = 0; 

printf("please enter the ID and how many seconds to calculate enter -1 when done\n"); 

while (1)       
{ 
    scanf_s("%d",&ID[i]); 
    scanf_s("%f",&seconds[i]); 

    if(ID[i] == Sentinel_Numb || seconds[i] == Sentinel_Numb){ 
     break; 
     } 
    i++; 
} 

return 0; 
} 

Answer 1

更改爲：

scanf_s("%d",&ID[i]); 
if (ID[i] == Sentinel_Numb) 
    break; 
scanf_s("%f",&seconds[i]); 
if (seconds[i] == Sentinel_Numb) 
    break; 

Answer 2

while (1)       
{ 
    scanf_s("%d",&ID[i]); 

    if (ID[i] == Sentinel_Numb) 
     break; 

    scanf_s("%f", &seconds[i]); 

    if (seconds[i] == Sentinel_Numb) 
     break; 
    i++; 
}