多線程服務器插槽的例外是不誠實的

最近我一直在使用的代碼，我發現上的多線程設計我的服務器多線程服務器插槽的例外是不誠實的

服務器啓動正常，並等待客戶，但是當客戶端連接我得到休耕錯誤：

Only one usage of each socket address (protocol/network address/port) is normally permitted

代碼：

public partial class Form1 : Form 
{ 
    Server s; 
    public Form1() 
    { 
     InitializeComponent(); 

     s = new Server(this); 
     s.StartTcpServer(); 
    } 
    private void Stop_Btn_Click(object sender, EventArgs e) 
    { 
     s.StopListenForClients(); 
    } 
    public void addButton(int x, int y, String text) 
    { 
     Button btn = new Button(); 
     btn.Size = new Size(50, 50); 
     btn.Location = new Point(x, y); 
     btn.Text = text; 
     btn.Visible = true; 
     this.Controls.Add(btn); 
    } 
} 
class Server 
{ 
    public event EventHandler recvdChanged; 
    private TcpListener tcpListener; 
    private Thread listenThread; 
    private string recvd; 
    Form1 _f1parent; 
    public Server(Form1 par) 
    { 
     _f1parent = par; 
    } 
    public string getsetrecvd 
    { 
     get { return this.recvd; } 
     set 
     { 
      this.recvd = value; 
      if (this.recvdChanged != null) 
       this.recvdChanged(this, new EventArgs()); 
     } 
    } 
    public void StartTcpServer() 
    { 
     this.tcpListener = new TcpListener(IPAddress.Any, 8000); 
     this.listenThread = new Thread(new ThreadStart(ListenForClients)); 
     this.listenThread.Start(); 
    } 
    static Boolean b = false; 
    private void ListenForClients() 
    { 
     //where are recive the error 
     this.tcpListener.Start(); 

     while (true) 
     { 
      //blocks until a client has connected to the server 
      TcpClient client = this.tcpListener.AcceptTcpClient(); 
      if (client.Connected) 
      { 
       b = true; 
      // MessageBox.Show(client.Client.RemoteEndPoint + " Has Connected."); 
      } 

      //create a thread to handle communication 
      //with connected client 
      Thread clientThread = new Thread(new ParameterizedThreadStart(HandleClientComm)); 
      clientThread.Start(client); 
      b = false; 
     } 
    } 
    public void StopListenForClients() 
    { 
     tcpListener.Stop(); 
    } 
    private void HandleClientComm(object client) 
    { 
     TcpClient tcpClient = (TcpClient)client; 
     NetworkStream clientStream = tcpClient.GetStream(); 

     byte[] message = new byte[4096]; 
     int bytesRead; 
     Form1 p = new Form1(); 
     while (true) 
     { 
      bytesRead = 0; 

      try 
      { 
       //blocks until a client sends a message 
       bytesRead = clientStream.Read(message, 0, 4096); 

      } 
      catch 
      { 
       //a socket error has occured 
       break; 
      } 

      if (bytesRead == 0) 
      { 
       //the client has disconnected from the server 
       break; 
      } 

      //message has successfully been received 
      ASCIIEncoding encoder = new ASCIIEncoding(); 
      getsetrecvd = encoder.GetString(message, 0, bytesRead); 
      if (recvd != "e") 
      { 
      } 
      else 
      { 
       break; 
      } 
     } 

     tcpClient.Close(); 
    } 
}

我調試的程序，它運行在ListenForClients while循環（）它接受客戶端後，再次運行while循環，但在

TcpClient client = this.tcpListener.AcceptTcpClient();

退出而停止，並顯示在我

this.tcpListener.Start();

什麼我做錯了錯誤？

來源

2013-11-03 Atom97

通過它的聲音，您試圖運行兩個偵聽器 - 在「AcceptTcpClient」停止的代碼是原始偵聽器：應該沒有其他線程嘗試同時運行tcpListener.Start。首先要做的是添加日誌記錄，包含託管線程ID - 這樣您就可以看到什麼線程在做什麼。您還可以查看調用tcpListener.Start的代碼的堆棧跟蹤以查看來自哪裏，因爲該不應該發生（此時監聽器已在運行）。

作爲設計要點：不建議使用thread-per-client。

來源

2013-11-03 11:15:43

如何添加包含託管線程ID的日誌記錄？ – Atom97

@Atom trace.writeline與文本中的Thread.CurrentThread.ManagedThreadId應該做 –

在ClientComm中創建新窗體時，您將開始一個新的listenThread。

Form1 p = new Form1();

如前所述，您只能在端口上偵聽一次，while循環將爲新連接生成線程。您應該嘗試捕獲acceptTCPClient，例如停止會給你一個例外，你需要趕上。

來源

2013-11-03 17:45:20 Ceelie

多線程服務器插槽的例外是不誠實的

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