我正在使用具有Boost Regex/Xpressive的命名捕獲組。C++ :: Boost :: Regex遍歷子匹配
我想遍歷所有submatches,並獲得每個submatch的值和KEY(即什麼[「type」])。
sregex pattern = sregex::compile( "(?P<type>href|src)=\"(?P<url>[^\"]+)\"" );
sregex_iterator cur(web_buffer.begin(), web_buffer.end(), pattern);
sregex_iterator end;
for(; cur != end; ++cur){
smatch const &what = *cur;
//I know how to access using a string key: what["type"]
std::cout << what[0] << " [" << what["type"] << "] [" << what["url"] <<"]"<< std::endl;
/*I know how to iterate, using an integer key, but I would
like to also get the original KEY into a variable, i.e.
in case of what[1], get both the value AND "type"
*/
for(i=0; i<what.size(); i++){
std::cout << "{} = [" << what[i] << "]" << std::endl;
}
std::cout << std::endl;
}