我怎樣才能把它們變成2個4的腳背組？

Question

所以這是我的代碼，它需要一個來自數據庫的人列表，並將他們與他們的合作伙伴分組。在這些組中，人員的用戶標識不能在同一行中出現兩次。一切正常，我只是想知道如何使它呼應4人，每組僅與2

if ($result = $mysqli->query("SELECT * FROM performers")) { 
printf("Found %d rows.\n", $result->num_rows); 

$rows = array(); 

while ($row = $result->fetch_array()) { 
    foreach ($row as $key => $col) { 
     unset($row[$key]); 
     $row[strtolower($key)] = $col; 
    } 
    $rows[] = $row; 
} 

$current = null; 
$count = 1; 
while (! empty($rows)) { 
    if ($current) { 
     $current_performers = array($current['performerid_1'], $current['performerid_2']); 
     $found = false; 
     foreach ($rows as $key => $row) { 
      if (! in_array($row['performerid_1'], $current_performers) && ! in_array($row['performerid_2'], $current_performers)) { 
       $found = $key; 
       break; 
      } 
     } 

     if ($found !== false) { 
      echo '<li>', $rows[$found]['performance_id'], ': ', $rows[$found]['perf_name_1'], ' - ', $rows[$found]['perf_name_2'], '</li>'; 
      unset($rows[$key]); 


     } 

     else { 
      echo ''; 
     } 

     echo '</ul><hr />'; 

     $current = null; 
    } else { 
     $current = array_shift($rows); 
     echo '<h3>Group ', $count+, '</h3>'; 
     echo '<ul>'; 
     echo '<li>', $current['performance_id'], ': ', $current['perf_name_1'], ' - ', $current['perf_name_2'], '</li>'; 
    } 
} 

Answer 1

我想這應該這樣做，但我沒有測試過（除了驗證語法），因爲我不沒有任何樣本數據。

$group_size = 4; 
$current_performers = array(); 
$current_size = 0; 
$count = 1; 
while (!empty($rows)) { 
    if ($current_size == $group_size) { // End previous group 
     echo '</ul><hr>'; 
     $current_performers = array(); 
     $current_size = 0; 
    } 
    if ($current_size == 0) { 
     echo '<h3>Group ', $count++, '</h3>'; 
     echo '<ul>'; 
    } 
    $found = false; 
    foreach ($rows as $key => $row) { 
     if (! in_array($row['performerid_1'], $current_performers) && ! in_array($row['performerid_2'], $current_performers)) { 
      $found = true; 
      array_push($current_performers, $row['performerid_1'], $row['performerid_2']); 
      $current_size++; 
      echo '<li>', $row['performance_id'], ': ', $row['perf_name_1'], ' - ', $row['perf_name_2'], '</li>'; 
      unset($rows[$key]); 
      break; 
     } 
    } 

    if (!$found) { 
     // Force a new group to start 
     $current_size = $group_size; 
    } 
    // If we have an unfinished group, finish it 
    if ($current_size) { 
     echo '</ul><hr>'; 
    } 

}