Underscore.js分組對象

是更多鈔票，以組對象，並結合Underscore.js所有屬性是這樣的：Underscore.js分組對象

[ 
    { menu: "Setting", role: "admin" }, 
    { menu: "Setting", role: "user" }, 
    { menu: "Setting", role: "developer" }, 
    { menu: "Application", role: "admin" }, 
    { menu: "Application", role: "user" }, 
]

弄成這個樣子：

[ 
    { menu: "Setting", admin: "OK", user: "OK", developer: "OK"}, 
    { menu: "Application", admin: "OK", user: "OK"}, 
]

來源

2017-02-15 stkertix

是的，也有可能與常規的老JS一樣。 – Adam

是的，我一直在嘗試與常規的JS，但我最終與循環，需要時間和內存，所以我想尋找替代品，如underscore.js :) – stkertix

_.map(_.groupBy(arr, 'menu'), function(roles, menu) { 
    var entry = {menu: menu}; 
    _.each(roles, function(role) { entry[role.role] = "OK"; }); 
    return entry; 
})

我假設你後面的輸出是：

[ 
    { "menu": "Setting", "admin": "OK", "user": "OK", "developer": "OK" }, 
    { "menu": "Application", "admin": "OK", "user": "OK" } 
]

來源

2017-02-15 17:00:31 mikeapr4

woaah，它適用於這樣一個簡單的腳本。感謝您的回答。：d – stkertix

Underscore.js分組對象

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