mysql的PHP不顯示的副本ID

Question

我想從這個查詢刪除重複的用戶名：

SELECT 
    transactions.id, 
    transactions.user_id, 
    transactions.dikaioma, 
    transactions.`in`, 
    users.`name` AS username, 
    users.score, 
    users.startDikaioma, 
    transactions.`out`, 
    games.`name`, 
    banks.bank_id, 
    banks.sxolio 
FROM 
    transactions 
INNER JOIN 
    users ON transactions.user_id = users.id 
INNER JOIN 
    games ON users.curgame = games.id 
INNER JOIN 
    posta ON users.posto_id = posta.posto_id 
INNER JOIN 
    banks ON posta.posto_bank_id = banks.bank_id 
WHERE 
    transactions.`in` NOT BETWEEN 0 AND 1 
ORDER BY 
    transactions.id DESC 
LIMIT 10 

有人可以幫助我如何 不從用戶的顯示重複的ID我嘗試

GROUP BY users.id HAVING count(users.id) > 1) 

但不工作..錯誤

Answer 1

嘗試在SELECT後面加上DISTINCT。這應該省略任何重複。

http://www.tutorialspoint.com/sql/sql-distinct-keyword.htm

Answer 2

您是否嘗試過使用上，你想不有重複列的DISTINCT函數。

SELECT DISTINCT 
transactions.id, 
transactions.user_id, 
transactions.dikaioma, 
transactions.`in`, 
users.`name` AS username, 
users.score, 
users.startDikaioma, 
transactions.`out`, 
games.`name`, 
banks.bank_id, 
banks.sxolio 
FROM 
transactions 
INNER JOIN users ON transactions.user_id = users.id 
INNER JOIN games ON users.curgame = games.id 
INNER JOIN posta ON users.posto_id = posta.posto_id 
INNER JOIN banks ON posta.posto_bank_id = banks.bank_id 
WHERE 
transactions.`in` NOT BETWEEN 0 AND 1 
ORDER BY 
transactions.id DESC 
LIMIT 10