Laravel遷移錯誤語法

Question

我想遷移（更新）這一點，但我不斷收到此錯誤信息：

[Symfony的\分量\調試\異常\ FatalErrorException]語法錯誤， 意外 '>' ，要求以 '<'

Schema::table('products', function (Blueprint $table)) { 
     $table->string('XXXX', 50)->change(); 
     $table->string('XXXX', 50)->change(); 
     $table->string('XXXX', 10)->change(); 
     $table->String('XXXX', 100)->change();; 
     $table->String('XXXX', 100)->change(); 
     $table->String('XXXX', 100)->change(); 
     $table->String('XXXX', 50)->change(); 
     $table->tinyInteger('XXXX')->unsigned()->change(); 
     $table->tinyInteger('XXXX')->unsigned()->change(); 
     $table->String('XXXX', 100)->change(); 
     $table->tinyInteger('XXXX')->unsigned()->change(); 
     $table->String('XXXX', 50)->change(); 
     $table->String('XXXX', 50)->change(); 
     $table->String('XXXX', 50)->change(); 
     $table->String('XXXX', 50)->change(); 
     $table->String('XXXX', 50)->change(); 
     $table->boolean('XXXX')->change(); 
     $table->boolean('XXXX')->change(); 
     $table->boolean('XXXX')->change(); 
     $table->boolean('XXXX')->change(); 
     $table->boolean('XXXX')->change(); 
     $table->boolean('XXXX')->change(); 
     $table->boolean('XXXX')->change(); 
     $table->boolean('XXXX')->change(); 
     $table->boolean('XXXX')->change(); 
     $table->text('XXXX')->change(); 
     $table->String('XXXX', 100)->change(); 
     $table->String('XXXX', 100)->change(); 
     $table->String('XXXX', 100)->change(); 
     $table->String('XXXX', 100)->change(); 
     $table->tinyInteger('XXXX')->unsigned()->change(); 
     $table->tinyInteger('XXXX')->unsigned()->change(); 
     $table->tinyInteger('XXXX')->unsigned()->change(); 
     $table->tinyInteger('XXXX')->unsigned()->change(); 
     $table->String('XXXX', 50)->change(); 
     $table->String('XXXX', 50)->change(); 
     $table->String('XXXX', 50)->change(); 
     $table->String('XXXX', 50)->change(); 
     $table->text('XXXX'); 
     $table->timestamps(); 
    }); 
} 

Answer 1

您在5日線有;;和也String代替string。

順便說一下，當您運行migrate命令時，您可以從其他文件（控制器，中間件，助手等）中獲取錯誤。

Answer 2

在Laravel Migration Documentation，它表示使用$table->string('XXXX',50);創建VARCHAR等效列。

因此，您的語句錯誤$table->String('XXXX', 50)->change();。您應該將所有String更改爲string。

PS：其實在聲明中$table->String('XXXX', 100)->change();;。你已經使用;;，但不要緊，將報告沒有錯誤。