使用WSSpringServlet的SOAP Web服務的Spring MVC應用程序

Question

我創建了一個簡單的Spring MVC Web應用程序，並嘗試使用JAX-WS commons RI實現將服務公開爲基於SOAP的JAX-WS服務。

在Tomcat 7上部署我的應用程序後，當我嘗試訪問我的Web服務時，收到404 Not Found：Invalid Request的消息。以下是我的配置，請幫助解決此問題。

的web.xml

<web-app version="2.5" xmlns="http://java.sun.com/xml/ns/javaee" 
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" 
    xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"> 

    <!-- The definition of the Root Spring Container shared by all Servlets and Filters --> 
    <context-param> 
     <param-name>contextConfigLocation</param-name> 
     <param-value>/WEB-INF/spring/root-context.xml</param-value> 
    </context-param> 

    <!-- Creates the Spring Container shared by all Servlets and Filters --> 
    <listener> 
     <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class> 
    </listener> 

    <!-- Processes SOAP Web Service requests --> 
    <servlet> 
     <servlet-name>jaxws-servlet</servlet-name> 
     <servlet-class>com.sun.xml.ws.transport.http.servlet.WSSpringServlet</servlet-class> 
     <load-on-startup>1</load-on-startup> 
    </servlet> 

    <servlet-mapping> 
     <servlet-name>jaxws-servlet</servlet-name> 
     <url-pattern>/ws/*</url-pattern> 
    </servlet-mapping> 

    <!-- Processes application requests --> 
    <servlet> 
     <servlet-name>appServlet</servlet-name> 
     <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class> 
     <init-param> 
      <param-name>contextConfigLocation</param-name> 
      <param-value>/WEB-INF/spring/appServlet/servlet-context.xml</param-value> 
     </init-param> 
     <load-on-startup>1</load-on-startup> 
    </servlet> 

    <servlet-mapping> 
     <servlet-name>appServlet</servlet-name> 
     <url-pattern>/</url-pattern> 
    </servlet-mapping> 

</web-app> 

WEB-INF /彈簧/ appServlet/servlet的context.xml中

<beans:bean id="customerService" class="com.home.service.CustomerService" /> 

    <!-- Web Service definition --> 
    <beans:bean id="customerWS" class="com.home.ws.CustomerWS"> 
     <beans:property name="customerService" ref="customerService" /> 
    </beans:bean> 

    <wss:binding url="/ws/CustomerServ"> 
     <wss:service> 
      <ws:service bean="#customerWS" /> 
     </wss:service> 
    </wss:binding> 

CustomerWS.java

@WebService 
@SOAPBinding(style = Style.DOCUMENT, use = Use.LITERAL) 
public class CustomerWS { 

    private CustomerService customerService; 

    @WebMethod 
    public Customer read(long id) { 
     return customerService.read(id); 
    } 

    public void setCustomerService(CustomerService customerService) { 
     this.customerService = customerService; 
    } 
} 

CustomerService.java

@Service 
public class CustomerService { 
    public Customer read(long id) { 
     Customer cust = null; 
     System.out.println("CustomerService.read invoked"); 

     return cust; 
    } 
} 

的pom.xml - 包括JAXWS彈簧

<dependency> 
     <groupId>org.jvnet.jax-ws-commons.spring</groupId> 
     <artifactId>jaxws-spring</artifactId> 
     <version>1.9</version> 
    </dependency> 

的依賴性有沒有錯誤，在構建或部署應用程序。當我訪問URL時，仍然看不到服務器日誌文件中的錯誤。但是，瀏覽器顯示消息 - 404未找到：無效請求

我試圖URL是 - http://localhost:8080/crrs/ws/CustomerServ?wsdl

如果我訪問我的HomeController，它工作正常。主頁按預期加載。

感謝任何幫助。提前致謝。

Answer 1

我正在嘗試做同樣的事情。我的代碼幾乎相同，我只是使用@Name和@Inject而不是@Service。

只需添加extends SpringBeanAutowiringSupport到@WebService類，它的工作

Answer 2

在web.xml中的servlet映射似乎是原因。

<servlet-mapping> 
    <servlet-name>jaxws-servlet</servlet-name> 
    <url-pattern>/ws/*</url-pattern> 
</servlet-mapping> 

[...] 

<servlet-mapping> 
    <servlet-name>appServlet</servlet-name> 
    <url-pattern>/</url-pattern> 
</servlet-mapping> 

命名appServlet彈簧DispatcherServlet需要照顧的所有URL的http://localhost:8080/crrs後，甚至http://localhost:8080/crrs/ws/CustomerServ?wsdl。

WSSpringServlet url-pattern無法到達。