Parse.com上的多對多關係Cloud Code

Question

我有一個班級「團隊」，可以有很多用戶。

每當用戶被添加到團隊中時，我需要創建一個從/到關係。每個用戶都可以評分並被所有隊友評分。

這是我的雲代碼。我似乎無法得到這個工作。

// add Team relations for every saved player 
Parse.Cloud.afterSave("Team", function(request) { 

    // Team being saved 
    var team = request.object, 
     relation = team.relation("players"), 
     query = relation.query(); 

     query.find({ 

      // players on this Team 
      success: function(results) { 

       // all players on this Team 
       var i, j, player, teammate; 
       for (i = 0; i < results.length; i++) { 
        player = results[i]; 

        // for each player add a new Rate relation (from/to) 
        for (j = 0; j < results.length; j++) { 
         teammate = results[i]; 

         // if it's same player, escape relation 
         if (player == teammate) { continue; } 

         var Rate = Parse.Object.extend("Rate"), 
          rate = new Rate(); 

         // create the relation from this player 
         var fromRelation = rate.relation('from'); 
          fromRelation.add(player); 

         // to every other player on the team 
         var toRelation = rate.relation('to'); 
          toRelation.add(teammate); 

          rate.save(null, { 
           success: function(_team) { 

           }, 
           error: function(_team, error) { 

           } 
          }); 
        } 
       } 

       response.success('rate relation success'); 

      }, 
      error: function(error) { 
       response.error('rate relation error'); 
      } 
     }); 

}); 

向隊中添加球員效果很好，它運行在客戶端。在數據瀏覽器

課程設置：

Answer 1

你的類是 「價格」，但您要使用此代碼：

var Rate = Parse.Object.extend("Rate"), 
         rate = new Rate(); 

變化

var Rate = Parse.Object.extend("Rates"), 
         rate = new Rate(); 

此外，請確定您的對象是在添加關係之前創建的。

     var Rate = Parse.Object.extend("Rate"), 
         rate = new Rate(); 

          [.... MOVED BELOW .....} 

         rate.save(null, { 
          success: function(_team) { 
          [.... now create and save relations ...] 
          }, 

Answer 2

解決了這個問題。

唯一討厭我的事實是，如果我嘗試，我得到一個錯誤：

「fromRelation期待_user，卻得到了_Team」，爲什麼呢？

player = results[i]; 
var fromRelation = rate.relation('from'); 
fromRelation.add(player); 

我要創建2個新的增值經銷商，fromPlayer和頂層，雖然它看起來愚蠢到我，反正它的工作原理。

Parse.Cloud.define("updateTeamPlayers", function(request, response) { 
    var Team = Parse.Object.extend("Team"), 
     team = new Team(); 
     team.id = request.params.id; 

    var relation = team.relation("players"), 
     query = relation.query(); 

    query.find({ 
     success: function(results) { 
      var i, j, player, teammate, queryArray = [], teammateRes = results; 

      for (i = 0; i < results.length; i++) { 
       player = results[i]; 

       // for each player add a new Rate relation (from/to) 
       for (j = 0; j < teammateRes.length; j++) { 
        teammate = teammateRes[j]; 

        // if it's same player, escape relation 
        if (player == teammate) { continue; } 

        var Rate = Parse.Object.extend("Rates"), 
         rate = new Rate(); 

        // create the relation from this player 
        var fromPlayer = new Parse.User(); 
         fromPlayer.id = player.id; 

        var fromRelation = rate.relation('from'); 
         fromRelation.add(fromPlayer); 

        // to every other player on the team 
        var toPlayer = new Parse.User(); 
         toPlayer.id = teammate.id; 

        var toRelation = rate.relation('to'); 
         toRelation.add(toPlayer); 

        queryArray.push(rate); 
       } 
      } 

      Parse.Object.saveAll(queryArray, { 
       success: function(_allsaved) { 
        response.success('rate save success:' + _allsaved); 
       }, 
       error: function(error) { 
        response.error('rate save error:' + error + ' =|= ' + error.message); 
       } 
      }); 

      // end suucess 
     }, 
     error: function() { 
      response.error("team failed"); 
     } 
    }); 
});